How to filter an array of URLs that match a pattern

Question

I've got an array with URLs in it like so:

$urls = array(
    "http://myurl.com/file/2222/file.rar",
    "http://myurl.com/file/2222/file.part1.rar",
    "http://myurl.com/file/2222/file.part2.rar",
    "http://myurl/file/2222/file.part3.rar",
    "http://myurl.com/file/2222/file.part4.rar"
);

I want to find any of the filenames to check if they are a part or a single file.

For example the result for the above should be:

$single = "http://myurl.com/file/2222/file.rar";
$splits = array("http://myurl.com/file/2222/file.part1.rar", "http://myurl.com/file/2222/file.part2.rar", "http://myurl.com/file/2222/file.part3.rar", "http://myurl.com/file/2222/file.part4.rar");

Im thinking i need to use in_array somehow but i'm not entirely sure. — Exoon
– Exoon, Commented Dec 18, 2013 at 21:11
How easily can you predict the file name? Do they follow a standard convention? — Dave
– Dave, Commented Dec 18, 2013 at 21:12
Yes they are always either NAME.rar or NAME.part.rar so i need to get all the URLS with part into one array and all the urls without part into another array — Exoon
– Exoon, Commented Dec 18, 2013 at 21:13

AbraCadaver · Accepted Answer · 2013-12-18 21:17:21Z

2

I like preg_grep():

$parts = preg_grep('/\.part\d+\.rar/', $urls);
$singles = array_diff($urls, $parts);

Or to do the opposite for the singles:

$singles = preg_grep('/\.part\d+\.rar/', $urls, PREG_GREP_INVERT);

answered Dec 18, 2013 at 21:17

AbraCadaver

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