Error in converting the json value using JQuery

Question

I am trying to get the value from the serverside but i can't get it..Here, i am trying to convert the json data using JSON.parse(); but it is not working in jQuery... i don't know how to solve this...

    $(document).ready(function() {  
            $.ajax({    
                url:'http://newslet.comxa.com/NewsRecord.php' ,
                    dataType:'json',
                success:function(output_string) {
                    temp=JSON.parse(output_string);
                for(var i=0;i<temp.length;i++)
                {
                     $('#level').append('<div>Title &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;:'+temp[i].Title+'<br>Source  &nbsp;&nbsp;&nbsp;:<a href='+temp[i].links+'>'+temp[i].Source+'</a><br>Category :'+temp[i].Category+'</div><hr>');
                 }                      
                }
             });
        });

i get this output when i am running these path 'http://newslet.comxa.com/NewsRecord.php'..

[{"Id":"2","Date":"","Title":"Hitachi Data Systems bets big on analytics","Source":"TOI","Category":"Corporate","links":"http:\/\/timesofindia.indiatimes.com\/tech\/tech-news\/software-services\/Hitachi-Data-Systems-bets-big-on-analytics\/articleshow\/26542988.cms?"},{"Id":"3","Date":"","Title":"British bike company Triumph drives into India","Source":"TOI","Category":"Industry","links":"http:\/\/timesofindia.indiatimes.com\/business\/india-business\/British-bike-company-Triumph-drives-into-India\/articleshow\/26542881.cms"}]

try using this function $.each($.parseJSON(data), function(id, row) {}) — Ahmad Gulzar
– Ahmad Gulzar, Commented Dec 18, 2013 at 5:16
if i run using this $.each($.parseJSOn(data),fun) function i get this output in console....[10:51:18.859] The character encoding of the HTML document was not declared. The document will render with garbled text in some browser configurations if the document contains characters from outside the US-ASCII range. The character encoding of the page must be declared in the document or in the transfer protocol. — kamesh
– kamesh, Commented Dec 18, 2013 at 5:22

A.T. · Accepted Answer · 2013-12-18 05:17:41Z

1

you need to stringify first json result.

var json = JSON.stringify([{"Id":"2","Date":"","Title":"Hitachi Data Systems bets big on analytics","Source":"TOI","Category":"Corporate","links":"http:\/\/timesofindia.indiatimes.com\/tech\/tech-news\/software-services\/Hitachi-Data-Systems-bets-big-on-analytics\/articleshow\/26542988.cms?"},{"Id":"3","Date":"","Title":"British bike company Triumph drives into India","Source":"TOI","Category":"Industry","links":"http:\/\/timesofindia.indiatimes.com\/business\/india-business\/British-bike-company-Triumph-drives-into-India\/articleshow\/26542881.cms"}]);

var temp = JSON.parse(json);

answered Dec 18, 2013 at 5:17

A.T.

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1 Comment

Nitin Varpe Over a year ago

I think he doesnt even need to do this can loop through output_string only

Nitin Varpe · Accepted Answer · 2013-12-18 05:31:32Z

0

Your string already is a valid json so there isnt any need to use

JSON.parse(output_string);

Check this fiddle http://jsfiddle.net/uDr6t/

answered Dec 18, 2013 at 5:31

Nitin Varpe

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3 Comments

kamesh Over a year ago

i tried what u said but in that i got this console error...[11:10:26.222] SyntaxError: JSON.parse: unexpected non-whitespace character after JSON data @ code.jquery.com/jquery-1.8.3.min.js:2

Nitin Varpe Over a year ago

can u create fiddle for same

Nitin Varpe Over a year ago

have u seen my fiddle?

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