Variable Assignment in a Loop

Question

I am writing a shell script that reads and reports out timestamps (the current timestamp is stored in $g2). Eventually I will be comparing the two timestamps.

I want to check if $t2 is empty - if it is, the store it as $g2. If not, then to replace $t2 as $t1, and store the new $g2 value as $t2.

I am trying to output this in a sudo csv style file - but when I attempt to run this script I keep getting command not found errors. Any suggestions?

if
    [[ -z "$t2" ]]
then
    $t2=$g2
    echo "$t1,0,0" >> just_time.txt
else
    $t2=$t1
    $t2=$g2
    echo "$t2,$t1,0" >> just_time.txt
fi

$t2 = replaced by the value of t2. So you want t2=$g2 and not $t2=$g2. — Olivier Dulac
– Olivier Dulac, Commented Dec 16, 2013 at 9:43

Ashish Gaur · Accepted Answer · 2013-12-16 09:33:17Z

1

Try this :

if
    [[ -z "$t2" ]]
then
    t2=$g2
    echo "$t1,0,0" >> just_time.txt
else
    t1=$t2
    t2=$g2
    echo "$t2,$t1,0" >> just_time.txt
fi

answered Dec 16, 2013 at 9:33

Ashish Gaur

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2 Comments

Dustin Cook Over a year ago

That has only just printed a single timestamp on each line.

Ashish Gaur Over a year ago

Can you post your whole shell script and the error you are getting?

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