<?PHP
$result = mysql_query($query);
$finalval=0;
while($row = mysql_fetch_array($result))
{
$finalval=$finalval."<a onClick='showContent("please display")'
href='#' >". $row['Title'] ."</a> <br>" ;
}
echo $finalval;
?>
<script language="javascript" type="text/javascript" >
function showContent(value)
{
alert value;
}
</script>
Guys please help me out and please please tell me in a php code on clicking link how to call javascript/ajax function..Thank you so much
try alert(value) instead of alert value
'showContent(". $row['ID'] .")'Try this one ,opening double quotes within double quotes you need to escape them \
$finalval=$finalval."<a onClick='showContent(\"please display\")'
href='#' >". $row['Title'] ."</a> <br>" ;
}
alert(value) in your js function <?PHP
$result = mysql_query($query);
$finalval = 0;
while ($row = mysql_fetch_array($result)) {
$finalval = $finalval."<a class='show-content' data-value='please display' href='#' >". $row['Title'] ."</a> <br>" ;
}
echo $finalval;
?>
With javascript querySelectorAll get all a links with class selector then handle them
<script language="javascript" type="text/javascript" >
var element = document.querySelectorAll(".show-content");
for (var link in element) {
element[link].onclick = function() {
showContent(this.getAttribute('data-value'));
};
}
function showContent(value){
alert(value);
}
</script>
with jQuery it is pretty stright forward,
<script language="javascript" type="text/javascript" >
$(document).ready(function(){
$("a.content").on('click', function(){
alert($(this).data('value'));
// or make a specific function call
});
});
</script>
Hope this will help you, and do not forget to escape the special charactors as mentioned by M Khalid Junaid
