Using and catching RangeError in javascript

Question

I'm about to throw an exception using RangeError and wanted to check that I'm using it correctly and how to best catch it.

I have a function that could throw a RangeError OR a TypeError like this

function saveNumber(val) {
  // Only accept numbers.
  if (typeof val !== 'number') {
    throw new TypeError();
  }

  // Error if the number is outside of the range.
  if (val > max || val < min) {
    throw new RangeError();
  }

  db.save(val);
}

I'd like to call it and only deal with the RangeError. What's the best way to do this?

Answer 1

try {
  saveNumber(...);
} catch (e) {
  if (e instanceof TypeError) {
    // ignore TypeError
  } 
  else if(e instanceof RangeError) {
    // handle RangeError
  }
  else {
    // something else
  } 
}

source

Answer 2

Straight from the MDN documentation on try - catch:

try {
    saveNumber(...);
} catch (e is instanceof RangeError) {
    // Do something
} catch (e) {
    // re-throw whatever you don't want to handle
    throw e;
}

Answer 3

slightly more elegant answer:

switch (error.constructor) {
    case NotAllowedError:
        return res.send(400);
    case NotFoundError:
        return res.send(404);
    default:
        return res.send(500);
}