Getting a filename and save it in a variable in Python

Question

I want to get the name of a file that gets created by some other process inside a folder. It's in a path where only this file exists. It's in this path:

/directory/which/only/contains/this/one/file/

The file's full filename could then be for example:

/directory/which/only/contains/this/one/file/xZqsdtae123456.txt

How can I get the name of this file (from the example above: xZqsdtae123456.txt) and then save it in a variable ?

sebastian_oe · Accepted Answer · 2013-12-03 09:36:31Z

3

Assuming the generated file is the only one (as stated):

import os
yourfile = os.listdir("/home/user/Desktop/directory_which_only_contains_this_one_file")[0]

answered Dec 3, 2013 at 9:36

sebastian_oe

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1 Comment

bapors Over a year ago

and how would one loop over the files under this directory assuming we dont have only one?

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