Looping with a while statement inside an if statement

Question

So in my code you have to guess a number if you under or overestimate. How do I get the while loop to loop back to the input so you can input another number?

#include <stdio.h>

int main(int argc, const char * argv[])
{
    int number = 45;

    printf("Please insert a number");
    scanf("%d", &number);


    if (number == 45){
        printf("good job! You got the number right.");
        return 0;
    }
    else if (number < 45){
        while (number < 45 || number > 45){
            printf("Your number is too low");
            return 1;
        }
    }
    else if (number > 45){
        printf("Your number is too high!");
        return 1;
    }
}

Answer 1

Just put a while (1) around your code and remove the one wrongly placed :

#include <stdio.h>

int main(int argc, const char * argv[])
{
    while (1) {
        int number = 45;

        printf("Please insert a number");
        scanf("%d", &number);


        if (number == 45){
            printf("good job! You got the number right.");
            return 0;
        }
        else if (number < 45){
            printf("Your number is too low");
        }
        else{
            printf("Your number is too high!");
        }
    }
}

return is closing the program. So you don't want to return when the user hasn't guessed your number.
while (1) is the loop which will only exit when return 0 is launched (when the player has won).

Also, your last else if is not needed. Replace it by a else, because it is the only remaining case.

Answer 2

Wrap your code with a loop:

int number = 45;

while (1) {
    printf("Please insert a number");
    if (scanf("%d", &number) != 1) {
        printf("not valid number, try again");
        continue;
    }
    if (number == 45){
        printf("good job! You got the number right.");
        return 0;
    }
    if (number < 45){
        printf("Your number is too low");
        continue;
    }
    if (number > 45){
        printf("Your number is too high!");
        continue;
    }
}

Note that you should also check the return value of scanf to find out whether the number has been successfully read.