91

I want to sort my objects in descending order using comparator.

class Person {
 private int age;
}

Here I want to sort a array of Person objects.

How can I do this?

1
  • 3
    For example: arr1.sort(Comparator.comparing(Person::getAge).reversed()); Commented Mar 9, 2021 at 4:23

7 Answers 7

137

You can do the descending sort of a user-defined class this way overriding the compare() method,

Collections.sort(unsortedList,new Comparator<Person>() {
    @Override
    public int compare(Person a, Person b) {
        return b.getName().compareTo(a.getName());
    }
});

Or by using Collection.reverse() to sort descending as user Prince mentioned in his comment.

And you can do the ascending sort like this,

Collections.sort(unsortedList,new Comparator<Person>() {
    @Override
    public int compare(Person a, Person b) {
        return a.getName().compareTo(b.getName());
    }
});

Replace the above code with a Lambda expression(Java 8 onwards) we get concise:

Collections.sort(personList, (Person a, Person b) -> b.getName().compareTo(a.getName()));

As of Java 8, List has sort() method which takes Comparator as parameter(more concise) :

personList.sort((a,b)->b.getName().compareTo(a.getName()));

Here a and b are inferred as Person type by lambda expression.

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3 Comments

Or you can just use Collections.reverseOrder(...) for descending sort.
@Prince Not a fan of that approach, it forces me to look at the original method to see how things are sorted to begin with (un-reversed.)
Worth mentioning that compareToIgnoreCase is also handy when comparing String objects, more often than not I use this instead of just compareTo
71

For whats its worth here is my standard answer. The only thing new here is that is uses the Collections.reverseOrder(). Plus it puts all suggestions into one example:

/*
**  Use the Collections API to sort a List for you.
**
**  When your class has a "natural" sort order you can implement
**  the Comparable interface.
**
**  You can use an alternate sort order when you implement
**  a Comparator for your class.
*/
import java.util.*;

public class Person implements Comparable<Person>
{
    String name;
    int age;

    public Person(String name, int age)
    {
        this.name = name;
        this.age = age;
    }

    public String getName()
    {
        return name;
    }

    public int getAge()
    {
        return age;
    }

    public String toString()
    {
        return name + " : " + age;
    }

    /*
    **  Implement the natural order for this class
    */
    public int compareTo(Person p)
    {
        return getName().compareTo(p.getName());
    }

    static class AgeComparator implements Comparator<Person>
    {
        public int compare(Person p1, Person p2)
        {
            int age1 = p1.getAge();
            int age2 = p2.getAge();

            if (age1 == age2)
                return 0;
            else if (age1 > age2)
                return 1;
            else
                return -1;
        }
    }

    public static void main(String[] args)
    {
        List<Person> people = new ArrayList<Person>();
        people.add( new Person("Homer", 38) );
        people.add( new Person("Marge", 35) );
        people.add( new Person("Bart", 15) );
        people.add( new Person("Lisa", 13) );

        // Sort by natural order

        Collections.sort(people);
        System.out.println("Sort by Natural order");
        System.out.println("\t" + people);

        // Sort by reverse natural order

        Collections.sort(people, Collections.reverseOrder());
        System.out.println("Sort by reverse natural order");
        System.out.println("\t" + people);

        //  Use a Comparator to sort by age

        Collections.sort(people, new Person.AgeComparator());
        System.out.println("Sort using Age Comparator");
        System.out.println("\t" + people);

        //  Use a Comparator to sort by descending age

        Collections.sort(people,
            Collections.reverseOrder(new Person.AgeComparator()));
        System.out.println("Sort using Reverse Age Comparator");
        System.out.println("\t" + people);
    }
}

3 Comments

this actually worked for me , and it's also a very easy solution (just one line) .
Is there a way to sort Strings in a TreeSet using a comparator like this? Same thing, People by age.
I've never used a TreeSet, but the API documentation says - The elements are ordered using their natural ordering, or by a Comparator provided at set creation time, depending on which constructor is used, so I would guess it is possible.
22

I would create a comparator for the person class that can be parametrized with a certain sorting behaviour. Here I can set the sorting order but it can be modified to allow sorting for other person attributes as well.

public class PersonComparator implements Comparator<Person> {

  public enum SortOrder {ASCENDING, DESCENDING}

  private SortOrder sortOrder;

  public PersonComparator(SortOrder sortOrder) {
    this.sortOrder = sortOrder;
  }

  @Override
  public int compare(Person person1, Person person2) {
    Integer age1 = person1.getAge();
    Integer age2 = person2.getAge();
    int compare = Math.signum(age1.compareTo(age2));

    if (sortOrder == ASCENDING) {
      return compare;
    } else {
      return compare * (-1);
    }
  }
}

(hope it compiles now, I have no IDE or JDK at hand, coded 'blind')

Edit

Thanks to Thomas, edited the code. I wouldn't say that the usage of Math.signum is good, performant, effective, but I'd like to keep it as a reminder, that the compareTo method can return any integer and multiplying by (-1) will fail if the implementation returns Integer.MIN_INTEGER... And I removed the setter because it's cheap enough to construct a new PersonComparator just when it's needed.

But I keep the boxing because it shows that I rely on an existing Comparable implementation. Could have done something like Comparable<Integer> age1 = new Integer(person1.getAge()); but that looked too ugly. The idea was to show a pattern which could easily be adapted to other Person attributes, like name, birthday as Date and so on.

9 Comments

Once upon a time there was a good habit to leave a comment to help the just downvoted author to improve his message.
I did not downvote, but compare * (-1) is prone to overflow. I did the same mistake in my initial post.
And the SortOrder should be set in the constructor and be final. Using a wrapper is an better approach I suppose: new Reverse(new PersonComparator())
Why did you not swap the parameters for descending sort order? That much easier: Integer age1 = sortOrder == ASCENDING ? person1.getAge() : person2.getAge(); Integer age2 = sortOrder == ASCENDING ? person2.getAge() : person1.getAge(); return age1.compareTo(age2);
What’s the rationale behind using compare * (-1) instead of a straight-forward -compare? Using negation when you want a negation is idiomatic and flipping the sign is cheaper than performing a multiplication.
|
16
String[] s = {"a", "x", "y"};
Arrays.sort(s, new Comparator<String>() {

    @Override
    public int compare(String o1, String o2) {
        return o2.compareTo(o1);
    }
});
System.out.println(Arrays.toString(s));

-> [y, x, a]

Now you have to implement the Comparator for your Person class. Something like (for ascending order): compare(Person a, Person b) = a.id < b.id ? -1 : (a.id == b.id) ? 0 : 1 or Integer.valueOf(a.id).compareTo(Integer.valueOf(b.id)).

To minimize confusion you should implement an ascending Comparator and convert it to a descending one with a wrapper (like this) new ReverseComparator<Person>(new PersonComparator()).

5 Comments

Now that's a bit confusing example, because String implements Comparable. And that -1 there isn't the most straighforward thing.
The best argument against -1 * x is that -1 * Integer.MIN_VALUE == Integer.MIN_VALUE. Which is not what you want. I swapped the arguments that's easier anyway.
And I guess it's a ReverseComparator, instead of Reserve...
well, that wasn't THE best argument. It was just confusing for beginners :) It still is, because it would require him to know what Comparable is, and realize that his Person doesn't implement it. But then - thinking IS a good thing :)
Integer.compare mentions the following in its documentation: The value returned is identical to what would be returned by: Integer.valueOf(x).compareTo(Integer.valueOf(y)), so you can use Integer.compare instead.
6

Using Google Collections:

class Person {
 private int age;

 public static Function<Person, Integer> GET_AGE =
  new Function<Person, Integer> {
   public Integer apply(Person p) { return p.age; }
  };

}

public static void main(String[] args) {
 ArrayList<Person> people;
 // Populate the list...

 Collections.sort(people, Ordering.natural().onResultOf(Person.GET_AGE).reverse());
}

Comments

0
package com.test;

import java.util.Arrays;

public class Person implements Comparable {

private int age;

private Person(int age) {
    super();
    this.age = age;
}

public int getAge() {
    return age;
}

public void setAge(int age) {
    this.age = age;
}

@Override
public int compareTo(Object o) {
    Person other = (Person)o;
    if (this == other)
        return 0;
    if (this.age < other.age) return 1;
    else if (this.age == other.age) return 0;
    else return -1;

}

public static void main(String[] args) {

    Person[] arr = new Person[4];
    arr[0] = new Person(50);
    arr[1] = new Person(20);
    arr[2] = new Person(10);
    arr[3] = new Person(90);

    Arrays.sort(arr);

    for (int i=0; i < arr.length; i++ ) {
        System.out.println(arr[i].age);
    }
}

}

Here is one way of doing it.

Comments

0

The java.util.Collections class has a sort method that takes a list and a custom Comparator. You can define your own Comparator to sort your Person object however you like.

Comments

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