Passing values through URL

Question

component.php

<script>
   jq142(document).ready( function() {
       new Paginator('<?php echo HOST_URL; ?>component_ajax.php');
});        
</script>

I need to pass the id from component.php file to component_ajax.php file. component_ajax.php will load on the component.php file.

component_ajax.php

$coid = $_GET['id'];
$products = $productObj->getFrontProductsbyComponents( $coid );

Explain me to that how to pass id to $coid?

new Paginator('<?php echo HOST_URL; ?>component_ajax.php?id="your id"'); — Rituraj ratan
– Rituraj ratan, Commented Oct 14, 2013 at 7:30
tried new Paginator('<?php echo HOST_URL; ?>component_ajax.php?id="your id"'); But it is not working. — user2877903
– user2877903, Commented Oct 14, 2013 at 7:33

emarref · Accepted Answer · 2013-10-14 08:10:04Z

1

You need to append the id to the component_ajax.php URL.

new Paginator('<?php echo HOST_URL; ?>component_ajax.php?id=<?php echo $your_id; ?>');

If the ID you need to pass to component_ajax.php is in JavaScript instead of PHP, append the ID to the URL with javascript.

<script>
    var your_id = 123;
    jq142(document).ready( function() {
        new Paginator('<?php echo HOST_URL; ?>component_ajax.php?id=' + your_id);
    });
</script>

edited Oct 14, 2013 at 8:10

answered Oct 14, 2013 at 7:56

emarref

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4 Comments

emarref Over a year ago

What is displayed when you print_r($_REQUEST) inside component_ajax.php?

emarref Over a year ago

That tells me the id is not being passed at all (as opposed to being a blank value), which suggests maybe your Paginator javascript might be removing the id parameter from the URL. Can you tell me more about the Paginator javascript? Is it custom code or is it a third party library with documentation you could link to?

user2877903 Over a year ago

aplusdesign.com.au/misc/pagination/pagination_jquery.php#p=1 This is the script I used to...

emarref Over a year ago

Pass the parameters in as an argument.

var ajaxParams = {"id":<?php echo $your_id ?>}; new Paginator('<?php echo HOST_URL; ?>component_ajax.php', {"xParams": ajaxParams});

emarref · Accepted Answer · 2013-10-14 09:26:51Z

0

Pass the ID in to your Paginator object as an argument.

var ajaxParams = {"id":<?php echo $your_id ?>};
new Paginator('<?php echo HOST_URL; ?>component_ajax.php', {"xParams": ajaxParams});

Source

answered Oct 14, 2013 at 9:26

emarref

1,3119 silver badges19 bronze badges

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