Passing function pointer to a function + function arguments

Question

I have a function which I would like to pass to another function as an argument (let's call it funX). Here's funX prototype:

void funX(const unsigned char *, unsigned char *, size_t, const somestruct *, unsigned char *, const int);

and my function (lets call it funY) which calls funX:

unsigned char * funY(unsigned char *in, unsigned char *out, size_t len, unsigned char *i, void *k, int ed, void (*f)(unsigned char *, unsigned char *, size_t, const void *, unsigned char *, const int))
{
    f(in, out, len, k, i, ed);
}

But I have some warnings while compiling:

test.c: In function ‘main’:
test.c:70:5: warning: passing argument 7 of ‘funY’ from incompatible pointer type [enabled by default]
test.c:11:17: note: expected ‘void (*)(unsigned char *, unsigned char *, size_t,  const void *, unsigned char *, const int)’ but argument is of type ‘void (*)(const unsigned char *, unsigned char *, size_t,  const struct somestruct *, unsigned char *, const int)’

Use typedef for signatures as suggested here. This makes declaring a function parameter easier. — Basile Starynkevitch
– Basile Starynkevitch, Commented Sep 1, 2013 at 18:34
the error message seems pretty clear, the function pointer type does not correspond to the function you want to pass. — AndersK
– AndersK, Commented Sep 1, 2013 at 18:39
The function pointer parameter in funY declaration is not the same type as the type of funX. Just the first difference: the first arg to funX is a const unsigned char * whereas the first arg of the function pointer is a unsigned char *. — LorenzoDonati4Ukraine-OnStrike
– LorenzoDonati4Ukraine-OnStrike, Commented Sep 1, 2013 at 18:40

P0W · Accepted Answer · 2013-09-01 18:39:19Z

3

See the warning and compare the prototypes

Expected:-

void (*)(unsigned char *,       unsigned char *, size_t,  const void *,              unsigned char *, const int)

Provided :-

void (*)(const unsigned char *, unsigned char *, size_t,  const struct somestruct *, unsigned char *, const int)

answered Sep 1, 2013 at 18:39

P0W

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Comments

user529758 · Accepted Answer · 2013-09-01 18:37:33Z

2

Did you read the entire error message?

You have some const- and other type mismatches (e. g. a pointer-to-struct instead of void *, etc.) in the signature of the two functions. Function types are compatible only if their signatures match exactly.

answered Sep 1, 2013 at 18:37

user529758

Comments

Ziffusion · Accepted Answer · 2013-09-01 18:38:45Z

1

Your signatures seem to be different. See below.

void funX(const unsigned char *, unsigned char *, size_t, --> const somestruct * <--, unsigned char *, const int);

void (*f)(unsigned char *, unsigned char *, size_t, --> const void * <--, unsigned char *, const int)

answered Sep 1, 2013 at 18:38

Ziffusion

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