Python - random.randint () issue

Question

After randomly generating a number, I check to see if the user's input matches. If it does, print one line, if not, print another. Even if the user guesses correctly, the other line prints.

chosenNumber = input ("Choose a number: ")
int (chosenNumber)
diceRoll = random.randint (1,3)
print ("The number rolled is: ",diceRoll)
if diceRoll == chosenNumber:
      print ("WINNER")
else:
      print ("LOSER")

Thank you for any help.

What's your question? What happens, and what were you expecting to happen? (Also, int(chosenNumber) won't do anything useful if you don't store the integer anywhere.) — user2357112
– user2357112, Commented Aug 22, 2013 at 0:03
Kudos for knowing that you can't compare a string to an integer and that you have to use int() :) — TerryA
– TerryA, Commented Aug 22, 2013 at 0:05

TerryA · Accepted Answer · 2013-08-22 00:03:25Z

3

int() does not turn the string to an integer in place because strings are immutable.

You can do:

chosenNumber = int(input ("Choose a number: "))

answered Aug 22, 2013 at 0:03

TerryA

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1 Comment

Aaron Chapman Over a year ago

That worked! Thanks! I knew I could cast it to an int. At first I had chosenNumber = input (int("Choose a number: ")).

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