xml parsing error with jquery

Question

Why do I get Invalid XML when I parse with jquery xml

$(document).ready(function() {
    var xml = '<?php echo XML_CONFIGS . '/feed_config.xml' ?>';
    $("#sql_config").click(function(e) {
     e.preventDefault();  
     xmlDoc = $.parseXML(xml ),
     $xml = $( xmlDoc ),
     $feed = $xml.find( "feed[id = 4]" );

     console.log($feed);
        var data = $('#sql').serialize();              
    });

The hosted xml http://ui.kakuki.de/feed_config.xml

<?xml version="1.0" encoding="UTF-8"?>
<config>
    <element>
        <feed id=" 4 ">
            <title>My Feed</title>
            <table>my_table</table>
            <link>http://testsite.com/export/export?myFeed=13&amp;myFormat=134251570</link>
            <feed_type>XML</feed_type>
        </feed>
        <query/>
    </element>
</config>

The XML you provided is valid. I guess, it differs from the one, stored in the xml variable. — Artyom Neustroev
– Artyom Neustroev, Commented Aug 15, 2013 at 7:58
Debug your code to see, if the value stored in xml variable is valid XML document. — Artyom Neustroev
– Artyom Neustroev, Commented Aug 15, 2013 at 8:02
Host the xml and share the link for that. It will be easier for us to see what's going wrong ... — The Dark Knight
– The Dark Knight, Commented Aug 15, 2013 at 8:09
All seems valid to me but your $xml.find will return an empty array as your id isn't 4 its " 4 " eg. "feed[id=\"4\"]" — Sphvn
– Sphvn, Commented Aug 15, 2013 at 8:13

Sphvn · Accepted Answer · 2013-08-16 03:45:28Z

1

The $.parseXML(xml) and XML all seems fine and loads for me in all browsers I have tested with.

However your $xml.find will return an empty array as your id is incorrect.

Your id isn't 4 its " 4 " so your find should be $xml.find("feed[id=\" 4 \"]")

Glad I could help.

answered Aug 16, 2013 at 3:45

Sphvn

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