I apoligize for my newbness but I'm not clearly understanding how to access variables within a function outside of the function. I understand that you need to pass them some how but I'm not 100% sure on the whys and hows.
Taking the below code for example, I want to use the var degree throughout the code outside of the function. How do I do it?
function DegreeToMil()
{
//Degree's to Mils: 1 Degree = 17.777778 Mils
var degree = 10;
var mils = degree * 17.777778;
return mils;
}
It is actually fairly simple, just define it outside of the function.
Edit: Updated with an example, and comments explaining what was done and how it works.
DegreesToMils.degrees = 10; /* This is a static variable declaration to make sure it isn't undefined
* See note 1 below */
function DegreesToMils(degrees) {
if (degrees !== undefined) {
DegreesToMils.degrees = degrees; /* If the parameter is defined,
* it will update the static variable */
}
var milsPerDegree = 17.777778; /* This is a variable created and accessible within the function */
return DegreesToMils.degrees * milsPerDegree; /* The function will return 177.77778 */
}
console.log(DegreesToMils.degrees); /* Prints 10, Note 1: This would be undefined if
* not declared before the first call to DegreesToMils() with a
* defined parameter
*/
console.log(DegreesToMils(10)); /* Prints 177.77778 */
console.log(DegreesToMils(9)); /* Prints 160.00000200000002, Sets DegreesToMils.degrees to 9 */
console.log(DegreesToMils.degrees); /* Prints 9 */
function DegreeToMil()
{
//Degree's to Mils: 1 Degree = 17.777778 Mils
var degree = 10;
var mils = degree * 17.777778;
var result = [degree, mils]; // it's an array
return result;
}
// use it like this
var myResult = DegreeToMil();
console.log(myResult[0]); // degree
console.log(myResult[1]); // mils
varwhich makes it global... a better answer would be toreturnthe vars that you want to use at the end of the functionvar degreeby just typingDegreeToMil.degreeDegreesToMils()with a defined parameter prior to attempting to accessDegreesToMils.degreeswithout including the definition line I included above the function, it will resolve asundefined. You may or may not care about it. Also, I did try making it so you wouldn't need the line outside of the function, but it would have still required a function call first. If someone else knows another way I hope they share it.