javascript search in array elements

Question

I have array like this:

var notes = ["user1,date:13/2/2008,note:blablabla", "user1,date:15/2/2008,note:blablabla", "user1,date:17/2/2008,note:blablabla", "user1,date:13/3/2008,note:blablabla"];

And I have

var search_date="17/2/2008";

I want to find last occurence of note and user for that note. Anyone knows how? Thanks in advance for your reply.

Have you tried anything yet? You're gonna have to loop through, parse each value, and see if it matches. — gen_Eric
– gen_Eric, Commented Jul 5, 2013 at 13:48

p e p · Accepted Answer · 2013-07-05 13:50:29Z

1

Try this:

var highestIndex = 0;
for (var i = 0; i < notes.length; i++){
    if (notes[i].indexOf(search_date) != -1){
        highestIndex = i;
    }
}
//after for loop, highestIndex contains the last index containing the search date.

Then to get the user, you can parse like this:

var user = notes[highestIndex].substring(0, notes[highestIndex].indexOf(',') - 1);

answered Jul 5, 2013 at 13:50

p e p

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4 Comments

Joel Cochran Over a year ago

Just be aware that indexOf isn't supported in IE8 and older. - stackoverflow.com/questions/3629183/…

p e p Over a year ago

Joel - thank you, but now this raises a question and I'm not 100% clear on the answer. I've read (for example, stackoverflow.com/questions/6829101/…) that indexOf on String (how I am using it) has existed since very early IE versions. I have read that indexOf support for Arrays does not exist for IE8 and below. I can't give a definitive answer on that without trying it, but it sounds like that's the case from other sources as well.

Joel Cochran Over a year ago

Oops - my mistake, I didn't read closely enough. Array indexOf is missing, but yes String's indexOf should work fine.

Marko Vasic Over a year ago

I know that there are similar solutions to this, but I marked this as answer because I used this solution. Thanks everyone for help.

Balint Bako · Accepted Answer · 2013-07-05 13:49:55Z

1

You can iterate the array and check the attribute

or

you can user underscore.js: http://underscorejs.org/#filter

answered Jul 5, 2013 at 13:49

Balint Bako

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Comments

Reason · Accepted Answer · 2013-07-05 13:51:07Z

1

for (var i = 0; i < notes; i++) {
    if (notes[i].indexOf(search_date) != -1) {
        // notes [i] contain your date
    }
}

answered Jul 5, 2013 at 13:51

Reason

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Comments

Willem Mulder · Accepted Answer · 2013-07-05 13:54:30Z

1

var match = JSON.stringify(notes).match("\"([^,]*),date\:"+search_date+",note\:([^,]*)\"");
alert(match[1]);
alert(match[2]);

works ;-)

answered Jul 5, 2013 at 13:54

Willem Mulder

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Comments

user405398 · Accepted Answer · 2013-07-05 13:53:07Z

Something like this:

var notes = ["user1,date:13/2/2008,note:blablabla", "user1,date:15/2/2008,note:blablabla", "user1,date:17/2/2008,note:blablabla", "user1,date:13/3/2008,note:blablabla"];
var search_date="17/2/2008";

var res = [];

for(var i = 0; i < notes.length; i++) {
  var note = notes[i];
  if(note.indexOf(search_date) !== -1) {
    res.push(note.substring(note.indexOf('note:') + 1), note.length);
  }
}

var noteYouWanted = res[res.length - 1];

Jon · Accepted Answer · 2013-07-05 13:58:33Z

For the last occurrence and if performance matters:

var notes = ['user1,date:13/2/2008,note:blablabla', 'user1,date:15/2/2008,note:blablabla', 'user1,date:17/2/2008,note:blablabla', 'user1,date:13/3/2008,note:blablabla'],
    search = '17/2/2008',
    notesLength = notes.length - 1,
    counter,
    highestIndex = null;

for (counter = notesLength; counter >= 0; counter--) {
    if (notes[counter].indexOf(search) !== -1) {
        highestIndex = counter;
        break;
    }
}

// do something with notes[highestIndex]

Misiu · Accepted Answer · 2013-07-05 20:17:48Z

0

var notes = ["user1,date:13/2/2008,note:blablabla", "user1,date:15/2/2008,note:blablabla", "user1,date:17/2/2008,note:blablabla", "user1,date:13/3/2008,note:blablabla"];

var search_date="17/2/2008";
var user, note;

$.each(notes, function(i) {
    var search = new RegExp('\\b' + search_date + '\\b','i');
    // if search term is found
    if (notes[i].match(search)) {
      var arr = notes[i].split(',');
      user = arr[0];
      note = arr[2].substr(5);
    }
}); // end loop

console.log(user);
console.log(note);

example here: http://jsfiddle.net/Misiu/Wn7Rw/

edited Jul 5, 2013 at 20:17

answered Jul 5, 2013 at 13:59

Misiu

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1 Comment

Misiu Over a year ago

@MrCkobe - click edit on top right, or use this link: jsbin.com/epexil/3/edit then on top click run with js

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