Regex match string conditions

Question

Since i'm not so good at regex how can i match some conditions in a string, StaticString_1number:1number:more than 1number.

Example:

string_3:0:12344555 - Match 
string_s:0:12344555 - No match 
string_3:s:12344555 - No match 
string_3:0:123s4555 - No match

Thanks.

Input - string_3:0:12344555 - it's ok regex matched Input - string_s:0:12344555 - not ok Input - string_3:s:12344555 - not ok Input - string_3:0:123s4555 - not ok — siloan
– siloan, Commented May 21, 2013 at 9:35

Santosh Panda · Accepted Answer · 2013-05-21 09:49:19Z

2

This Regex would solve your problem:

^[a-zA-Z]+_[\d]{1}:[\d]{1}:[\d]+$

You can check this link for verification: http://regexr.com?34uj5

answered May 21, 2013 at 9:49

Santosh Panda

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user1019830 · Accepted Answer · 2013-05-21 09:42:02Z

1

If I understand your pattern StaticString_1number:1number:more than 1number correctly your regex to match against such strings could look like the following:

'^[a-zA-Z]+_[0-9]:[0-9]:[0-9]+$'

or if your environment support character classes:

'^\w+_\d:\d:\d+$'

answered May 21, 2013 at 9:42

user1019830

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sp00m · Accepted Answer · 2013-05-21 09:37:49Z

1

This should suit your needs:

^[^_]+_\d:\d:\d+$

Demo

answered May 21, 2013 at 9:37

sp00m

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olly_uk · Accepted Answer · 2013-05-21 09:39:22Z

0

If the initial String can only have characters a-z then the following should work :

[a-z A-Z]+_\d:\d:\d+

this will match any number of letters up to an underscore then look for single digit before and after colon and multiple digits after second colon.

but you should really have an attempt your self. if in python you could try re-try or in javascript regexpal and try out your regex patterns there first.

answered May 21, 2013 at 9:39

olly_uk

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Sri · Accepted Answer · 2013-05-21 09:47:20Z

0

This may help : ^[a-zA-Z]*_[0-9]:[0-9]:[0-9]*$

answered May 21, 2013 at 9:47

Sri

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