I have two lists
l1= [1,2,3,4,5,6,7]
l2 = [1,2,3,4,5,6,7,8,9,77,66,]
I want to display them on same lines
"list1 text" "list2 text"
l1-1 , l2-1
l1-2 , l2-2
and so on
so that if list elements finish then it should display blank "" in front of it but other side shows its own elements like
for a,b in l1,l2
<td>a</td><td> b </td>
You can use izip_longest with a fillvalue of whitespace,
>>> from itertools import izip_longest
>>> for a,b in izip_longest(l1,l2,fillvalue=' '):
... print a,b
...
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8
9
77
66
Something like this?
from itertools import izip_longest
l1= [1,2,3,4,5,6,7]
l2 = [1,2,3,4,5,6,7,8,9,77,66,]
for a,b in izip_longest(l1,l2, fillvalue=''):
print '"'+str(a)+'"','"'+str(b)+'"'
Out:
"1" "1"
"2" "2"
"3" "3"
"4" "4"
"5" "5"
"6" "6"
"7" "7"
"" "8"
"" "9"
"" "77"
"" "66"
Itertools.izip_longest can be used to combine the two lists, the value None will be used as a placeholder value for "missing" items in the shorter list.
>>>l1= [1,2,3,4,5,6,7]
>>l2 = [1,2,3,4,5,6,7,8,9,77,66,]
>>>n = ((a,b) for a in l1 for b in l2)
>>>for i in n:
i
for more details please go through this link: Hidden features of Python
for i in itertools.product(l1, l2): to do the same thing>>> l1= [1,2,3,4,5,6,7]
>>> l2 = [1,2,3,4,5,6,7,8,9,77,66,]
>>> def render_items(*args):
... return ''.join('<td>{}</td>'.format('' if i is None else i) for i in args)
...
>>> for item in map(render_items, l1, l2):
... print item
...
<td>1</td><td>1</td>
<td>2</td><td>2</td>
<td>3</td><td>3</td>
<td>4</td><td>4</td>
<td>5</td><td>5</td>
<td>6</td><td>6</td>
<td>7</td><td>7</td>
<td></td><td>8</td>
<td></td><td>9</td>
<td></td><td>77</td>
<td></td><td>66</td>
l1= [1,2,3,4,5,6,7]
l2 = [1,2,3,4,5,6,7,8,9,77,66]
maxlen = max(len(l1),len(l2))
l1_ext = l1 + (maxlen-len(l1))*[' ']
l2_ext = l2 + (maxlen-len(l2))*[' ']
for (a,b) in zip(l1_ext,l2_ext):
print a,b
l1= [1,2,3,4,5,6,7]
l2 = [1,2,3,4,5,6,7,8,9,77,66]
for (a,b) in map(lambda a,b:(a or ' ',b or ' '), l1, l2):
print a,b