Printf in for loop doesn't work without a printf preceded outside the loop

Question

I've been having this problem: when I try to print an array with 2 for loops nothing happens, blank screen. When I add a printf preceding the loop (anything like printf("1");) the loop printing shows in the execution. The code:

for(j=0;j<i;j++){
    printf("\n");
    for(k=0;k<i;k++){
        printf("%6d",*(polje+j*i+k));
    }
}

Not only does the program not print the loop, it says x.exe stopped working if I don't use another printf outside the loop.

Answer 1

Try to call fflush(stdout); after your second printf.

Answer 2

Try this:

for(j=0;j<i;j++){
    printf("\n");
    for(k=0;k<i;k++){
        printf("%6d",(polje+j*i+k));
    }
}

I removed * in the second printf.. It was multiplying anything oh the right side