Is the following correct?
var z1=^[0-9]*\d$;
{
if(!z1.test(enrol))
{
alert('Please provide a valid Enrollment Number');
return false;
}
}
Its not currently working on my system.
6 Answers
You can test it as:
/^\d*$/.test(value)
Where:
- The
/at both ends mark the start and end of the regex - The
^and$at the ends is to check the full string than for partial matches \d*looks for multiple occurrences of number charcters
You do not need to check for both \d as well as [0-9] as they both do the same - i.e. match numbers.
var numberRegex = /^\s*[+-]?(\d+|\d*\.\d+|\d+\.\d*)([Ee][+-]?\d+)?\s*$/
var isNumber = function(s) {
return numberRegex.test(s);
};
"0" => true
"3." => true
".1" => true
" 0.1 " => true
" -90e3 " => true
"2e10" => true
" 6e-1" => true
"53.5e93" => true
"abc" => false
"1 a" => false
" 1e" => false
"e3" => false
" 99e2.5 " => false
" --6 " => false
"-+3" => false
"95a54e53" => false
1 Comment
AbdulRehman
This works great. Thanks. Was tearing my hair out trying to find a just such a solution. Can also use just
^\s*[+-]?(\d+|\d*\.\d+|\d+\.\d*)?\s*$ if you don't require the scientific notation support.Try:
var z1 = /^[0-9]*$/;
if (!z1.test(enrol)) { }
Remember, * is "0 or more", so it will allow for a blank value, too. If you want to require a number, change the * to + which means "1 or more"
Comments
You this one and it allows one dot and number can have "positive" and "negative" symbols
/^[+-]?(?=.)(?:\d+,)*\d*(?:\.\d+)?$/.test(value)
Comments
If you looking for something simple to test if a string is numeric, just valid numbers no +, - or dots.
This works:
/^\d*$/.test("2412341")
true
/^\d*$/.test("2412341")
false
Comments
you can also use this regular expression for number validation
/^\\/(\d+)$/
/^[0-9]*\d$/. You could also use/^\d+$/. Note that if the test passes, it just means its all digits, it isn't necessarily a valid enrolment number.