pass variable from ajax to php

Question

i have 1 php file name index.php. in that file i want to pass one variable from ajax to php.

var elem = document.getElementById("mydiv").value;
(function($)
{
    $(document).ready(function()
    {   
        $.ajax(
        {   
            type:"POST",
            url: window.location.href,
            data: 'action='+elem,
            beforeSend: function() {
                $('#cctv').hide();
            },
            complete: function() {
                $('#cctv').show();
            },
            success: function() {
                $('#cctv').show();
            }
        });
        var $container = $("body");
        $container.load('findAllPath.php',{'function': 'findAllPath'});
        var refreshId = setInterval(function()
        {
            $container.load('findAllPath.php',{'function': 'findAllPath'});
        }, 10000);
    });
})(jQuery);

and my php

if (isset ($_POST['action']))
{   
    echo $_POST['action'];
}

in firebug, i can see that ajax already post 'action=value' but in php, $_POST['action'] is empty. anyone can help me, what's wrong with my code? thank you

Does the isset test pass? Is it set but just to an empty string? — Dutts
– Dutts, Commented Mar 19, 2013 at 9:41
From where on the page is this javascript executed? For example, is it inside the <head> tag, or at the bottom, near </body>? — Sverri M. Olsen
– Sverri M. Olsen, Commented Mar 19, 2013 at 9:47

Subodh Ghulaxe · Accepted Answer · 2013-03-20 05:05:23Z

4

Try using data like this

data: {action: elem},

For Example

$.ajax({
   type: "POST",
   url: "some.php",
   data: { name: "John", action: "save" }
   }).done(function( msg ) {
  alert( "Data Saved: " + msg );
});

printr whole $_REQUEST and check if your are getting action

edited Mar 20, 2013 at 5:05

answered Mar 19, 2013 at 9:44

Subodh Ghulaxe

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Comments

imclickingmaniac · Accepted Answer · 2013-03-19 09:42:41Z

1

set this as json object:

data: {action: elem}

and don't mix jquery with pure js.

var elem = $('#myDiv').val();

and as friend above say. There can be situation where js is trying to get value property before whole page is loaded. You should do everything in document ready block.

You can also do:

data: {
action: $('#myDiv').val()
}

You will be sure then that you have the newest data on the form!

answered Mar 19, 2013 at 9:42

imclickingmaniac

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Comments

Subodh Ghulaxe · Accepted Answer · 2015-12-13 05:07:08Z

1

Look in to this and find what you have missed

    $.ajax({
        type: "POST",
        url: "some.php",
        data: { action: elem}
        beforeSend: function() {
            $('#cctv').hide();
        },
        complete: function() {
            $('#cctv').show();
        },
        success: function() {
            $('#cctv').show();
        }
    });
    var $container = $("body");
    $container.load('findAllPath.php',{'function': 'findAllPath'});
    var refreshId = setInterval(function()
    {
        $container.load('findAllPath.php',{'function': 'findAllPath'});
    }, 10000);
});

edited Dec 13, 2015 at 5:07

Subodh Ghulaxe

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answered Mar 19, 2013 at 9:59

Thirumalai murugan

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2 Comments

Yessie Setiawan Over a year ago

hmm?i don't get it,, if you mean url: "some.php" and not window.location.href, is not make any different

Thirumalai murugan Over a year ago

data: 'action='+elem, this is the wrong one, are you not getting answer or unable to understand?

Ihor Patychenko · Accepted Answer · 2013-03-19 11:16:13Z

0

if (!empty($_POST['action']))
{   
echo $_POST['action'];
}

Try this code...

answered Mar 19, 2013 at 11:16

Ihor Patychenko

1966 silver badges19 bronze badges

1 Comment

Yessie Setiawan Over a year ago

but $_POST['action'] is undefined, so empty test will not pass

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