I have a string, shown below
A123459922
I want to remove A and add B with Regex to the end of it. How can I do it using regex
Regex.Replace("A123459922","(\w{1})(\d*)");
I don't know exactly how can I remove the first character and Add 'B' to the end of it? to ended up something like this
123459922B
I'll use the same regex of your question.
You could look at this (for more complex situations)
Regex.Replace("A123459922",@"(\w{1})(\d*)", m => m.Groups[2].Value + "B");
See the 3rd parameter of the Replace method. It is a MatchEvaluator, which receives a Match and returns the replacement string. The above expressions is equivalent to:
private static void Main()
{
Regex.Replace("A123459922",@"(\w{1})(\d*)", Evaluator);
}
private static string Evaluator(Match m) {
return m.Groups[2].Value + "B";
}
You're basically saying: I want to replace the entire match by the 2nd group + the B character
According to your given input and output string example, you can do this simply with Substring():
var newString = myString.Substring(1) + "B";
Try using this regex:
Regex.Replace("A123459922", @"\w(.*)", "$1B");
Bneeded to be added only when there's anAin the beginning? Or always regardless?A, you can also usestring.Replacewhich is faster but will also match any and allAeven the ones you might want to keep.