Access global variable inside the scope of an array function [duplicate]

Question

I'm trying to write a filter script using an array filter function in PHP using the lambda syntax.

This achieves what I want to do, but it looks like it can be optimised:

$offersReceivedProcessedByItem = array();
  foreach ($this->currentSessionUser->items as $item) {
    $receivedOffersOnItem = array();
    foreach ($offersReceived as $offerReceived) {
     if ($offerReceived->item->id === $item->id) {
       $receivedOffersOnItem[$offerReceived->id] = $offerReceived;
     }
    }
  offersReceivedProcessedByItem[$item->id] = $receivedOffersOnItem;
}

(for each item a user has, filter through the offersReceived array and add the offer to a new array if it has an equal id, if that makes sense?!).

Here's what I'm trying:

$offersReceivedProcessedByItem = array();
foreach ($this->currentSessionUser->items as $item) {
   $receivedOffersOnItem = array_filter($item->offers, function($offer){
     return $offer->item->id === $item->id;
   });
   $offersReceivedProcessedByItem[$item->id] = $receivedOffersOnItem;
}

But I'm getting that $item is undefined, I expect it's closed scope so I tried passing $item as another argument but then I'm getting 'missing argument 2'.

I tried this using the relational approach built into Fuel but PHP eats too much memory and fails.

KingCrunch · Accepted Answer · 2013-02-14 21:38:10Z

2

A closure doesn't know anything about the environment it is created it unless you tell it

$receivedOffersOnItem = array_filter($item->offers, function($offer) use($item){
   return $offer->item->id === $item->id;
});

Notice the use-statement

A link to the manual http://php.net/functions.anonymous#example-119

edited Feb 14, 2013 at 21:38

answered Feb 14, 2013 at 21:27

KingCrunch

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