I have this array,
var arr1 = [19, 1, 1, 1, 1];
and another array,
var arr2 = ["Default", "Dynamic", "Assessment", "Risk", "Privacy"];
What I would like is to merge them somehow such that it would look something like this,
var merged_array = [ ["Default", 19], ["Dynamic", 1], ["Assessment", 1], ["Risk", 3], ["Privacy", 2] ];
how would I do that? I tried join but I did not achieve what I wanted. Thanks in advance!
Using a for loop:
var merged_array = new Array(arr1.length);
for (var i = 0; i < arr1.length; i++) {
merged_array[i] = new Array(arr2[i], arr1[i]);
}
This assumes arr1 and arr2 have the same length.
arr1.length and arr2.length are of both the same.
If you have jquery or equivalent:
var merged_array = $.map(arr1, function(e, i) {
return [arr2[i], e];
});
If not, then just use a for loop, same idea.
var merged_array = []
for (var i = 0; i < arr1.length && i < arr2.length; i++) {
merged_array[i] = [arr2[i], arr1[i]];
}
var result = new Array();
for (var i=0; i<arr1 .length && i<arr2.length ; i++) {
result[i] = new Array();
result[i][0] = arr1[i];
result[i][1] = arr2[i];
}
I'd probably extend the array object especially if this is a common task. Something like this:
Array.prototype.myMerge = function(arr){
var returnArr = [];
for(var i = 0, len = this.length; i < len; i++){
returnArr[i] = [this[i], arr[i]];
}
return returnArr;
};
then you could call it like this:
var merged_array = arr1.myMerge(arr2)
Of course you'd have to add some error checking on the length of the arrays, this function assumes that arr1 is longer or the same length as arr2. But that depends on what you want to do if arr1 and arr2 are different lengths, your question seems to assume they are the same length.
If you include the library underscore.js (prototype.js also has something similar), you can use _.zip(array1,array2). They provide example usage with 3 arrays.
From http://underscorejs.org/#zip :
zip_.zip(*arrays) Merges together the values of each of the arrays with the values at the corresponding position. Useful when you have separate data sources that are coordinated through matching array indexes. If you're working with a matrix of nested arrays, zip.apply can transpose the matrix in a similar fashion.
_.zip(['moe', 'larry', 'curly'], [30, 40, 50], [true, false, false]);
=> [["moe", 30, true], ["larry", 40, false], ["curly", 50, false]]
forloop works? Try that.for, I never thought of using that one either. But I'll try that later. Cheers!for(), thanks for the tip! :)