I am currently creating a class with a constexpr constructor and I wonder if I can use an std::array to store the data of this class. Does the standard explicitly specify that an std::array has a constexpr constructor and that its contents can be accessed at compile-time ?
2 Answers
Because std::array<T, N> is an aggregate, it can be initialized as a constexpr if and only if the underlying type T has a constexpr constructor (when presented with each initializer you provide).
Comments
Based on the comment by @MarkGlisse: this compiles
#include <array>
#include <iostream>
template<typename T, std::size_t N>
struct X
{
constexpr X(const std::array<T,N>& a):arr(a){}
private:
std::array<T,N> arr;
};
constexpr std::array<int,2> a {{ 13, 18 }};
constexpr X<int,2> x = a;
int main()
{
}
I believe I have found the relevant quote from the Standard here:
12.1 Constructors [class.ctor]
6 A default constructor that is defaulted and not defined as deleted is implicitly defined when it is odrused (3.2) to create an object of its class type (1.8) or when it is explicitly defaulted after its first declaration. The implicitly-defined default constructor performs the set of initializations of the class that would be performed by a user-written default constructor for that class with no ctor-initializer (12.6.2) and an empty compound-statement. If that user-written default constructor would be ill-formed, the program is ill-formed. If that user-written default constructor would satisfy the requirements of a constexpr constructor (7.1.5), the implicitly-defined default constructor is constexpr.
This looks essentially like @BenVoigt's answer.
5 Comments
Marc Glisse
#include <cstdlib> #include <array> template<typename T, std::size_t N> struct X { constexpr X(std::array<T,N>& a):arr(a){} private: std::array<T,N> arr; }; std::array<int,2> a = { 13, 18 }; X<int,2> x = a; compiles for me...
TemplateRex
@MarcGlisse Try adding
constexpr in front of a and X, and it won't compile!Marc Glisse
#include <cstdlib> #include <array> template<typename T, std::size_t N> struct X { constexpr X(const std::array<T,N>& a):arr(a){} private: std::array<T,N> arr; }; constexpr std::array<int,2> a = { 13, 18 }; constexpr X<int,2> x = a; compiles just fine.TemplateRex
@MarcGlisse OK, tnx, so any clue why it compiles? ;-)
Marc Glisse
chris said it, std::array is an aggregate. What part exactly confuses you?
std::arraydoes not have aconstexprconstructor to the best of my knowledgestd::arrayhas no (user-defined) constructor. It's an aggregate.constexprto various functions. So you cannot get your data in aconstexprmanner in C++11 but this should be resolved in the next language version (and possibly sooner depending on your library implementor) to mark most of them (all?) asconstexpr.