sort specific index in array in descending order

Question

I have an array called look. It contains 10 items in it. How do i sort index 7 to 9 in the array in descending order? below is code i use sort index 0 to 6 in ascending.

Arrays.sort(look, 0, 6);

yeah. i saw collections.reverseorder. but it seems it doesn't allow to specify the index number to sort. — FredHomme
– FredHomme, Commented Dec 8, 2012 at 14:02

Philip Whitehouse · Accepted Answer · 2012-12-08 14:02:04Z

2

Arrays.sort(look, 7, 9, Collections.reverseOrder());

should work.

answered Dec 8, 2012 at 14:02

Philip Whitehouse

4,1673 gold badges25 silver badges37 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

micha · Accepted Answer · 2012-12-08 14:01:42Z

0

You can use the Arrays method:

public static <T> void sort(T[] a, int fromIndex, int toIndex, Comparator<? super T> c)

With help of the Comparator interface you can define you own sorting mechanism.

see: public static void sort(T[] a, int fromIndex, int toIndex, Comparator c)) and Comparator

answered Dec 8, 2012 at 14:01

micha

49.8k16 gold badges75 silver badges80 bronze badges

Collectives™ on Stack Overflow

sort specific index in array in descending order

2 Answers 2

Comments

Comments

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Related