Concatenating all elements in list into a string python

Question

This one should be quick but for some reason I can't think of it. So say I have a list of elements n length (the number of elements will change at some point in the future). However, let's use this one as an example:

['ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13']

Now what I would like is to output this into a string that looks like this:

("ESZ12", "ESH13", "ESM13", "ESU13, "ESZ13")

The first one is indeed a list of elements and the second is just a complete string.

Thanks

2nd one is not a string, it's a tuple. You can get it using tuple(your_list). — Rohit Jain
– Rohit Jain, Commented Nov 28, 2012 at 17:17

NPE · Accepted Answer · 2012-11-28 17:19:58Z

4

In [4]: l = ['ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13']

In [5]: print('(' + ', '.join('"%s"' % el for el in l) + ')')
("ESZ12", "ESH13", "ESM13", "ESU13", "ESZ13")

answered Nov 28, 2012 at 17:19

NPE

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3 Comments

Ashwini Chaudhary Over a year ago

I would simply do str(tuple(l)).

NPE Over a year ago

@AshwiniChaudhary: The output of that would use different quotes to what's specified in the question. More generally, the format would be entirely at the mercy of the Python implementation, and outside the programmer's control.

Ashwini Chaudhary Over a year ago

How about print str(tuple(lis)).replace("'",'"').

Ian G · Accepted Answer · 2012-11-28 17:21:39Z

3

If you want a string that looks like a tuple the easiest way is convert to a tuple:

>>> l = ['ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13']
>>> str(tuple(l))
"('ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13')"

answered Nov 28, 2012 at 17:21

Ian G

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5 Comments

Ashwini Chaudhary Over a year ago

@Aniket how's it wrong, just do print str(tuple(l)), what you're seeing is a repr() version , that is due to the console.

Aniket Inge Over a year ago

The output needed "(double quotation) and not single quotation.

Aniket Inge Over a year ago

("ESZ12", "ESH13", "ESM13", "ESU13", "ESZ13") is required, and the output is "('ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13')"

Ashwini Chaudhary Over a year ago

@Aniket that can be easily managed by replace() : str(tuple(lis)).replace("'",'"')

Aniket Inge Over a year ago

@AshwiniChaudhary without the replace() it is wrong output. And that's what my comment was about.

Thomas Leonard · Accepted Answer · 2012-11-28 17:20:02Z

2

use join function :

>>> a = ['ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13']
>>> '("' + '", "'.join(a) + '")'
'("ESZ12", "ESH13", "ESM13", "ESU13", "ESZ13")'

answered Nov 28, 2012 at 17:20

Thomas Leonard

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Comments

Jakob Bowyer · Accepted Answer · 2012-11-28 17:19:24Z

0

Turn it into a string?

"".join(my_list)

Turn it into a tuple?

my_tuple = tuple(my_list)

answered Nov 28, 2012 at 17:19

Jakob Bowyer

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Comments

Aniket Inge · Accepted Answer · 2012-11-28 17:19:38Z

0

the expected output is a tuple. If you really meant string, then you can use:

strx = ''
strx.join(list)

answered Nov 28, 2012 at 17:19

Aniket Inge

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1 Comment

Jakob Bowyer Over a year ago

Please don't name a variable after a builtin

mpjan · Accepted Answer · 2012-11-28 17:25:53Z

0

Is this what you mean?:

    x = ['ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13']
    y = str(tuple(x))
    print y

You get:

    "('ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13')"

As a result.

answered Nov 28, 2012 at 17:25

mpjan

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Comments

James Waldby - jwpat7 · Accepted Answer · 2012-11-28 18:23:14Z

0

Although % formatting has been deprecated, there are cases where it is useful. For example, the code

x = ['ESZ12', 'ESH13', 'ESM13', 'ESU13', 'ESZ13']
print '("%s")' % '", "'.join(x)

produces:

("ESZ12", "ESH13", "ESM13", "ESU13", "ESZ13")

Of course, changing the print to

print '("{}")'.format('", "'.join(x))

gives the same result, without using deprecated %.

answered Nov 28, 2012 at 18:23

James Waldby - jwpat7

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