I have a number that is submitted by the user.
I want to make something like this: 1568301
to an array like this: 1, 5, 6, 8, 3, 0, 1.
How can I do this without adding "," between every digit or something like that? (type int).
Thanks.
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When you say (type int), do you mean that you want the array to be of type int?Martin Ellis– Martin Ellis2012-11-22 15:42:26 +00:00Commented Nov 22, 2012 at 15:42
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8 Answers
String str = "123456";
str.toCharArray();
will do roughly what you want. A more complex version using a regular expression is:
String str = "123456";
str.split("(?<!^)");
which uses a negative lookbehind (split() takes a regexp - the above says split on anything provided the element to the left isn't the start-of-line. split("") would give you a leading blank string).
The second solution is more complex but gives you an array of Strings. Note also that it'll give you a one-element empty array for a blank input. The first solution gives you an array of Chars. Either way you'll have to map these to Integers (perhaps using Integer.parseInt() or Character.digit()?)
Comments
"1568301".toCharArray() should do the job.
Comments
You can use the Split with "" It'll be like this:
String test = "123456";
String test2[] = test.split("");
for (int i = 1; i < test2.length; i++) {
System.out.println(test2[i]);
}
1 Comment
Brian Agnew
Don't forget to check for an input of "" otherwise this will blow up!
If your number is in String format, you can simply do this:
String str = "1568301";
char[] digitChars = str.toCharArray();
Comments
Are expecting something like this
String ss ="1568301";
char[] chars = ss.toCharArray();
Comments
cant you simply populate the array by iterating over the String ??
char[] arr = new char[str.length];
for(int i=0; i<str.length; i++){
arr[i] = str.charAt(i);
}
or even better
char[] arr = "0123456".toCharArray();
Comments
To get the values in an array of integers:
String str = "1568301";
int[] vals = new int[str.length];
for (int i = 0; i < str.length(); i++) {
vals[i] = Character.digit(str.charAt(i), /* base */ 10));
}
The second parameter of Character.digit(char, int) is the number base. I'm assuming your number is base 10.
Comments
I guess you are looking at to have an array of int.
I would suggest to have the following code :
String str = "1568301";
int [] arr = new int[str.length()];
for(int i=0; i<arr.length; i++)
{
arr[i] = str.charAt(i)-'0';
}
3 Comments
Saurabh
why negative, can someone please explain?
Martin Ellis
I didn't mean to downvote your answer, but the site won't let me change my vote until you've edited your answer. If you add even a single space, I can fix my vote.
Martin Ellis
Fixed! Sorry for the clumsiness.