jQuery AJAX call to PHP Controller

Question

I am calling a controller (Codeigniter) through jQuery. My dataString variable contains a simple string, which I'm trying to pass through to my controller, so I can pass it into the model. However, I'm getting an error that indicates that my $test_var is undefined. What am I doing wrong?

$('a.test').click(function (event) {


    dataString = $(this).attr('name'); 
        $.ajax({
        type:"POST",
        url:"<?php echo base_url(); ?>controller_name/",
        data:dataString,
        success:function (data) {
        alert('test');
        }

    });
    event.preventDefault();
});

controller

$test_var= $this->input->post('dataString');

John Conde · Accepted Answer · 2012-11-15 21:41:18Z

3

Try using a name=value pair:

$('a.test').click(function (event) {


    dataString = $(this).attr('name'); 
        $.ajax({
        type:"POST",
        url:"<?php echo base_url(); ?>controller_name/",
        data:'dataString='+dataString,
        success:function (data) {
        alert('test');
        }

    });
    event.preventDefault();
});

answered Nov 15, 2012 at 21:41

John Conde

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Comments

ianace · Accepted Answer · 2012-11-16 08:42:24Z

you could also do something like this, which is an alternative syntax

$('a.test').click(function (event) {
    dataString = $(this).attr('name'); 
    $.ajax({
        type:"POST",
        url:"<?php echo base_url(); ?>controller_name/",
        data:{'dataString':dataString},
        success:function (data) {
        alert('test');
        }
    });
    event.preventDefault();
});

in your controller $test_var= $this->input->post('dataString');

or just like in vanilla php

$test_var = $_POST['dataString'];

mohan.gade · Accepted Answer · 2012-11-24 19:22:11Z

0

use data option like this data: { name: "John", location: "Boston" } for more details plz check http://api.jquery.com/jQuery.ajax/

answered Nov 24, 2012 at 19:22

mohan.gade

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