Php generate random and different numbers

Question

I create this in php for generate random numbers

> <?php
> 
> $products=array("1","2","3","4","5","6","7","8","9","10");
> 
> for ($i=0;$i<count($products);$i++) {
> 
> $numbers=rand(0,count(products));
> 
> print "".$products[$numbers]."<br>";
> 
> } ?>

I try generate in bucle different numbers but always show me the same numbers 1212121212 and nothing more , how i can generate this string or array and for example finally show 2 3 4 1 5 6 7 9 8 10 , and if reload script other combination

Thank´s Regards !!!

count(products) shouldn't it be count($products)?

TheZ
– TheZ

2012-11-07 21:26:52 +00:00
Commented Nov 7, 2012 at 21:26 — TheZ
– TheZ, Commented Nov 7, 2012 at 21:26
You could simply shuffle the array.

Gumbo
– Gumbo

2012-11-07 21:27:43 +00:00
Commented Nov 7, 2012 at 21:27 — Gumbo
– Gumbo, Commented Nov 7, 2012 at 21:27

Niet the Dark Absol · Accepted Answer · 2012-11-07 21:28:55Z

2

You forgot the $ in count($products). As a result, the parser is treating it as the string "products", which has a count() of 1. Therefore, the rand() function returns zero or one, which in your original array correspond to "1" and "2".

answered Nov 7, 2012 at 21:28

Niet the Dark Absol

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1 Comment

Gerardo Guzmán Miro Over a year ago

Yes i solve that i put bad when i insert the post , but the problem continue , because many numbers repit all time and no able get different numbers and no repit , thank´s

Teena Thomas · Accepted Answer · 2012-11-07 21:29:15Z

1

Try using shuffle,

$products=array("1","2","3","4","5","6","7","8","9","10"); 
shuffle($products);
foreach($products as $v)
 echo $v;

Demo

answered Nov 7, 2012 at 21:29

Teena Thomas

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