c++ struct array definition

Question

I am wondering if there is a better way to simply create a struct containing an array with a SIZE:

...
#define SIZE 100;
...

struct foo {
    foo();
    bar * bars;
}

foo::foo() {
bars = new bar[SIZE];
}

Well, SIZE is a compile time constant, so you do not need a dynamically alocated array. You can have a bar bars[SIZE] data member. — juanchopanza
– juanchopanza, Commented Nov 3, 2012 at 22:10

Michael Krelin - hacker · Accepted Answer · 2012-11-03 22:09:59Z

4

as long as SIZE is a compile-time constant you can simply

struct foo {
    bar bars[SIZE];
}

answered Nov 3, 2012 at 22:09

144k25 gold badges200 silver badges177 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1