Creating a Java List of Generic types

Question

I have created a Java class MyObject:

public class MyObject
{
    public final String s; 
    public final int i; 
    public final int j;
    ...
}

I want to create a List of this type, but I am getting a "Cannot instantiate the type List" error

private java.util.List<MyObject> myObjectss = new java.util.List<MyObject>();

I tried the solution in this question (4 vote answer) but I get a "The type List is not generic; it cannot be parameterized with arguments " error...

Java Linked List How to create a node that holds a string and an int?

arshajii · Accepted Answer · 2012-10-10 03:01:26Z

4

List is an interface and therefore cannot be instantiated. You could try:

private java.util.List<MyObject> myObjectss = new java.util.ArrayList<MyObject>();

ArrayList is a class that implements the List interface.

Edit Just saw that you needed a LinkedList, try this:

private java.util.List<MyObject> myObjectss = new java.util.LinkedList<MyObject>();

answered Oct 10, 2012 at 3:01

arshajii

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4 Comments

Luiggi Mendoza Over a year ago

OP needs LinkedList. It's pretty similar but still the answer could have better guidance.

spatara Over a year ago

ah, I see now. I thought I might have been using List wrong...but not how. Thanks!

Luiggi Mendoza Over a year ago

Also, you can instantiate an interface in your code by creating an anonymous class, but it's clumsy to use it for the List interface.

arshajii Over a year ago

Yes you can do this also. I don't remember if this would be called "instantiating List" since you are technically implementing it in an anonymous class and then instantiating that class. But anyway, that's a technicality.

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