#!/bin/bash
if [ -z "$1" ]
then
echo "No argument supplied"
exit
fi
if [ "$1"="abc" ] ; then
abc
exit
fi
if [ "$1" = "def" ]; then
def
exit 1
fi
function abc()
{
echo "hello"
}
function def()
{
echo "hi"
}
Here abc is a function which has local definition. But Bash is giving error "./xyz.sh: line 10: abc: command not found". Please give me any Solution?
All functions must be declared before they can be used, so move your declarations to the top.
Also, you need to have a space on either side of the = in your string comparison test.
The following script should work:
#!/bin/bash
function abc()
{
echo "hello"
}
function def()
{
echo "hi"
}
if [ -z "$1" ]
then
echo "No argument supplied"
exit
fi
if [ "$1" = "abc" ] ; then
abc
exit
fi
if [ "$1" = "def" ]; then
def
exit 1
fi
case statement, by the way. case $1 in abc) abc; exit;; def) def; exit 1;; esacecho "$0: No argument supplied" >&2 with the script name in the message and the redirect to standard error.I suspect there is a problem with your declaration of abc. If you provide the code for your script, we'll be more able to provide specific help, but here is an example of what I think you are trying to achive.
#!/bin/bash -x
abc(){
echo "ABC. bam!"
}
foo="bar"
if [ "$foo"="bar" ]; then
abc
else
echo "No bar for you"
fi
