Command line arguments passing in python

Question

Hi I am new to Python and have currently copied following script:

# filename is printer.py
import sys
for arg in sys.argv:
    print arg    # the zeroth element is the module name
raw_input("press any key")    # a trick to keep the python console open

I am trying to get the arguments followed by the module name. But running this code gives me following error:

U:\printer.py
    File "U:\printer.py", line 6
      print arg # zeroth element is the module name
              ^
SyntaxError: Invalid syntax

Does anyone know what could be wrong here? I am using Python 3.2

score 5 · Accepted Answer · 2012-09-18 10:26:38Z

5

In Python 3 print is a function:

print(arg)

edited Sep 18, 2012 at 10:26

answered Sep 18, 2012 at 10:18

user647772

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Comments

mgilson · Accepted Answer · 2012-09-18 10:37:30Z

5

As noted by others, in python3, print is a function:

print arg

is now:

print(arg)

Also, raw_input is gone and replaced by simply input. (in py2k, input would eval the string from the commandline, but it won't do that in py3k).

Finally (and maybe most importantly), have you considered argparse? (untested code follows)

import argparse
parser = argparse.ArgumentParser()
parser.add_argument('foo',nargs='*',help="What a nice day we're having")
args = parser.parse_args()
print(args.foo)

edited Sep 18, 2012 at 10:37

answered Sep 18, 2012 at 10:32

mgilson

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1 Comment

Wooble Over a year ago

Also, "press any key" is a lie, whether you're using raw_input or input.

Some programmer dude · Accepted Answer · 2012-09-18 10:19:27Z

2

Python 3 no longer has a print keyword, but a print function.

Try instead

print(arg)

answered Sep 18, 2012 at 10:19

Some programmer dude

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