Share variables between bash scripts

Question

I am trying to make an init.d script to launch my app. I have two scripts, the first one is the init.d script myapp :

   #!/bin/bash
   export MYAPP_HOME="/srv/myapp"
   su - myuser -c "exec $COMMAND_LINE"

The second is a script to launch myapp.

I want to use the variable MYAPP_HOME in the second script.

Can anybody help me ?

Your su command can't access the environment of the caller, so your exported variable will not be available. You would need to pass it as a command line argument. — Mike Weller
– Mike Weller, Commented Sep 11, 2012 at 10:11
@MikeWeller, thats simply not true. su <username> -c "<command>" inherits the current environment. The OP's issue is that they had -, specifying a login shell. — jedwards
– jedwards, Commented Sep 12, 2012 at 17:17

cdarke · Accepted Answer · 2012-09-11 10:20:42Z

4

The problem is that you are creating a login shell by using the - argument to su, so a new environment is created. Either don't use a login shell (omit the -), pass the variable as a command-line argument, or place the environment variable in one of the start-up files, like .bash_profile.

answered Sep 11, 2012 at 10:20

cdarke

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