I have a string like this:
S(08-01-2008) I[18] ф4(579.1900 UAH) E(05-07-2009)R[5](117.1900) V[0](0.0000) Up(22-04-2009)
I need get Up value: 22-04-2009
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2So what is your question? What have you tried? What's wrong at all ?Teneff– Teneff2012-08-30 11:35:32 +00:00Commented Aug 30, 2012 at 11:35
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@Teneff the problem is I can do that on C#, but I don't know javascriptWachburn– Wachburn2012-08-30 11:39:36 +00:00Commented Aug 30, 2012 at 11:39
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@Wachburn You don't get the point! Your question is unclear!JeanValjean– JeanValjean2012-08-30 11:40:32 +00:00Commented Aug 30, 2012 at 11:40
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@Wachburn : I don't see how he could be more clear.bokan– bokan2012-08-30 11:42:33 +00:00Commented Aug 30, 2012 at 11:42
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Show us what (pseudo) C# code would solve your problem - we don't know about your string format and can only guessBergi– Bergi2012-08-30 11:48:59 +00:00Commented Aug 30, 2012 at 11:48
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3 Answers
Try
'S(08-01-2008) I[18] ф4(579.1900 UAH) E(05-07-2009) R5 V0 Up(22-04-2009)'
.match(/Up\(.+\)/g);
It returns an array of matched values, here ["Up(22-04-2009)"]
Value only could be:
'S(08-01-2008) I[18] ф4(579.1900 UAH) E(05-07-2009) R5 V0 Up(22-04-2009)'
.match(/Up\(.+\)/g)[0].split(/\(|\)/)[1];
Or
'S(08-01-2008) I[18] ф4(579.1900 UAH) E(05-07-2009) R5 V0 Up(22-04-2009)'
.match(/Up\(.+\)/g)[0].replace(/Up\(|\)/g,'');
If you're not sure 'Up(...)' exists in the string:
( 'S(08-01-2008) I[18] ф4(579.1900 UAH) E(05-07-2009) R5 V0 Up(22-04-2009)'
.match(/Up\(.+\)/g) || ['not found'][0] )
.replace(/Up\(|\)/g,'');
1 Comment
Wachburn
how can i get value between brackets?
extract = yourString.substr( -11,10);
It will extract 10 chars starting by the 11th counting from end.
This assume that the up value is always at the end of your input string.
This one is much faster than regex, or split solutions if you just need one value.
More example at : http://www.bennadel.com/blog/2159-Using-Slice-Substring-And-Substr-In-Javascript.htm
Comments
You can easily match a regular expression or get some substring from a certain (or computed) position, but let's try to parse it with a regex and split:
var str = "S(08-01-2008) I[18] ф4(579.1900 UAH) E(05-07-2009)R[5](117.1900) V[0](0.0000) Up(22-04-2009)";
var parts = str.split(/\s*\(\s*(.+?)\s*\)\s*/);
var map = {};
for (var i=0; i+1<parts.length; i+=2)
map[parts[i]] = parts[i+1];
Now, you can get the "Up" value from the map via
return map["Up"]; // "22-04-2009"
In contrast to the other answers, this will result in undefined if there is no "Up" value in the string instead of throwing an exception. Also, you can get the other values from the map if you need them, for example map["I[18] ф4"] is "I[18] ф4".
