C++ array of structures initialization

Question

I have the following structure:

struct localframepos
{
    double ipos; //local room frame i(x) coordinate, in mm
    double cpos; //local room frame c(y) coordinate, in mm
    double rpos; //local room frame r(z) coordinate, in mm

    localframepos()
    {
        ipos = 0;
        cpos = 0;
        rpos = 0;
    }
    localframepos(double init_ipos, double init_cpos, double init_rpos) //init constructor
    {
        ipos = init_ipos;
        cpos = init_cpos;
        rpos = init_rpos;
    } 
};

How do I get the following functionality:

localframepos positions[] = { {0, .5, .2},
                              {4.5, 4, .5} };

Luchian Grigore · Accepted Answer · 2012-08-10 01:17:31Z

3

Remove the constructors. To use curly brace initialization, the type has to be a POD.

edited Aug 10, 2012 at 1:17

answered Aug 10, 2012 at 1:14

Luchian Grigore

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4 Comments

Jesse Good Over a year ago

Why C++11, this is simple aggregate initialization.

anthonyvd Over a year ago

@CodeKingPlusPlus Plain Old Data

Luchian Grigore Over a year ago

@JesseGood does C++03 support intializing arrays with pod's?

Cheers and hth. - Alf Over a year ago

-1 "To use curly brace initialization, the type has to be a POD." is incorrect for C++03 (any aggregate can be initialized with curly braces syntax), and it is even more incorrect for C++11.

klm123 · Accepted Answer · 2012-08-10 02:05:37Z

0

I usually use

localframepos positions[] = { localframepos(0  , .5, .2),
                              localframepos(4.5, 4, .5) };

which is not that nice looking, but much more flexible if you need different initialization possibilities.

answered Aug 10, 2012 at 2:05

klm123

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Comments

Cheers and hth. - Alf · Accepted Answer · 2012-08-10 02:09:56Z

0

For C++03 you can write

localframepos positions[] = { localframepos( 0, .5, .2 ),
                              localframepos( 4.5, 4, .5 ) };

answered Aug 10, 2012 at 2:09

Cheers and hth. - Alf

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