adding trailing zeros to php string if not in format

Question

Have a text box which get data for price. If someone enter something like "3." i want to get it converted to "3.0" i cannot append "0" simply in the end because then if it is "100" gets converted to "1000"

Also is_numeric("3.") returns 1.

Whats the possible way round?

search for a decimal point being the last character in a the string, if it is, add a zero after? — Jamie
– Jamie, Commented Jul 5, 2012 at 10:27
did that, was searching is there is a function to do that other way — amitchhajer
– amitchhajer, Commented Jul 5, 2012 at 10:51

Sergey Eremin · Accepted Answer · 2012-07-05 10:57:05Z

3

You need number_format():

number_format('3', 1, '.', ''); // = 3.0
number_format('3.', 1, '.', ''); // = 3.0
number_format('3.22', 1, '.', ''); // = 3.2
number_format('3.22abc', 1, '.', ''); // = 3.2 and a "PHP Notice:  A non well formed numeric value encountered"
number_format('abc3.22', 1, '.', ''); // = "PHP Warning:  number_format() expects parameter 1 to be double, string given"

edited Jul 5, 2012 at 10:57

answered Jul 5, 2012 at 10:29

Sergey Eremin

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3 Comments

amitchhajer Over a year ago

what if my number is in string format? floatval is not converting it. Any idea?

Sergey Eremin Over a year ago

I've echoed the result and it is 3.0... floatval will stop conversion on first non-number symbol, so "3", "3.", "3.1234567" will work. "3.123456abc" will give you a notice. "abc123" will give you a warning.

runamok Over a year ago

@amitchhajer - cast the number to a float first? Such as: number_format((float) '3.22', 1, '.', ''); The only drawback to this approach is that number_format returns a string and not a float or int.

Kasia Gogolek · Accepted Answer · 2012-07-05 10:53:46Z

0

Try casting it as a float first, and then using number_format to format it.

$number = (float) $_POST['text_box'];
number_format($number, 1, '.', '');

Hope this helps

answered Jul 5, 2012 at 10:53

Kasia Gogolek

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Comments

Whisperity · Accepted Answer · 2012-07-05 11:09:36Z

0

You will need to use number_format() for this.

number_format($number, 1, ".", ""); will do the trick for you:

3 becomes 3.0
2500 becomes 2500.0

edited Jul 5, 2012 at 11:09

answered Jul 5, 2012 at 10:29

Whisperity

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4 Comments

Brandon - Free Palestine Over a year ago

Yeah, it looks the the OP wants valid numbers, so change the fourth parameter from " " to ''.

Whisperity Over a year ago

@RogueCoder Eh... it was an oversight. Thanks for the notice, I've edited the answer.

Brandon - Free Palestine Over a year ago

You actually need to add the '' as the fourth parameter since it defaults to ','.

Whisperity Over a year ago

@RogueCoder I didn't know that. Apparently, on my system it defaults to ''. Might be locale differencies.

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