I need to replace all digits.
My function only replaces the first digit.
var s = "04.07.2012";
alert(s.replace(new RegExp("[0-9]"), "X")); // returns "X4.07.2012"
// should be XX.XX.XXXX"
5 Answers
You need to add the "global" flag to your regex:
s.replace(new RegExp("[0-9]", "g"), "X")
or, perhaps prettier, using the built-in literal regexp syntax:
.replace(/[0-9]/g, "X")
3 Comments
Cmag
How would I replaced them with a unicode character instead of
X? For instance \U2022 ?Cmag
answer:
replace(/[0-9]/g, '\u2022');
Irfan Raza
This works only if string has all digits. Doesn't work with "test123"
Use
s.replace(/\d/g, "X")
which will replace all occurrences. The g means global match and thus will not stop matching after the first occurrence.
Or to stay with your RegExp constructor:
s.replace(new RegExp("\\d", "g"), "X")
Comments
find the numbers and then replaced with strings which specified. It is achieved by two methods
Using a regular expression literal
Using keyword RegExp object
Using a regular expression literal:
<script type="text/javascript">
var string = "my contact number is 9545554545. my age is 27.";
alert(string.replace(/\d+/g, "XXX"));
</script>
**Output:**my contact number is XXX. my age is XXX.
for more details:
http://www.infinetsoft.com/Post/How-to-replace-number-with-string-in-JavaScript/1156
Comments
The /g modifier is used to perform a global match (find all matches rather than stopping after the first)
You can use \d for digit, as it is shorter than [0-9].
JavaScript:
var s = "04.07.2012";
echo(s.replace(/\d/g, "X"));
Output:
XX.XX.XXXX
[0-9]can be simplified to\d.