Displaying JSON data with PHP

Question

I have the following array

"forecast":{
    "txt_forecast": {
    "date":"11:00 PM EDT",
    "forecastday": [
    {
    "period":0,
    "icon":"partlycloudy",
    "icon_url":"http://icons-ak.wxug.com/i/c/k/partlycloudy.gif",
    "title":"Saturday",
    "fcttext":"Partly cloudy in the morning, then mostly cloudy. High of 88F. Winds from the South at 5 to 10 mph.",
    "fcttext_metric":"Partly cloudy in the morning, then mostly cloudy. High of 31C. Winds from the South at 10 to 15 km/h.",
    "pop":"0"
    }
    ,
    {
    "period":1,
    "icon":"partlycloudy",
    "icon_url":"http://icons-ak.wxug.com/i/c/k/partlycloudy.gif",
    "title":"Saturday Night",
    "fcttext":"Overcast in the evening, then partly cloudy. Low of 64F. Winds less than 5 mph.",
    "fcttext_metric":"Overcast in the evening, then partly cloudy. Low of 18C. Winds less than 5 km/h.",
    "pop":"10"
    }

How would I display the information in PHP? It goes all the way up to period 7.

EDIT: Here is my edited code that is not working.

<?php
$json_string =    file_get_contents("http://api.wunderground.com/api/7ec5f6510a4656df/geolookup/forecast/q/40121.json");
$parsed_json = json_decode($json_string);
$temp = $parsed_json->{'forecast'}->{'txt_forecast'}->{'date'};
$title = $parsed_json->{'forecast'}->{'txt_forecast'}->{'forecastday'}->{'title'};
$for = $parsed_json->{'forecast'}->{'txt_forecast'}->{'forecastday'}->{'fcttext'};
echo "Current date is ${temp},  ${title}: ${for}\n";

foreach($parsed_json['forecast']['forecastday[0]'] as $key => $value)
{
   echo $value['period'];
   echo $value['icon'];
   // etc
}
?>

Note that your JSON is invalid: you need to surround it in { }, or remove "forecast": . Plus, you never close your square brackets. — Eric
– Eric, Commented Jun 10, 2012 at 10:08
Looks like you want the alternate form of decoding: my answer — Eric
– Eric, Commented Jun 10, 2012 at 10:10
Note that $parsed_json->{'forecast'}->{'txt_forecast'}->{'forecastday'}->{'fcttext'} is equivalent to $parsed_json->forecast->txt_forecast->forecastday->fcttext — Eric
– Eric, Commented Jun 10, 2012 at 10:10
I guess im missing what you mean on this.. Could you show me? — David Morin
– David Morin, Commented Jun 10, 2012 at 10:11

Community · Accepted Answer · 2020-06-20 09:12:55Z

8

Update

$json_string =    file_get_contents("http://api.wunderground.com/api/7ec5f6510a4656df/geolookup/forecast/q/40121.json");
$parsed_json = json_decode($json_string, true);
$parsed_json = $parsed_json['forecast']['txt_forecast']['forecastday'];
//pr($parsed_json);

foreach($parsed_json as $key => $value)
{
   echo $value['period'] . '<br>';
   echo $value['icon'] . '<br>';
   // etc
}

Result:

0
chancetstorms
1
tstorms
2
tstorms
3
tstorms
4
tstorms
5
partlycloudy
6
partlycloudy
7
partlycloudy

You will have to use json_decode() function for that.

$myArray = json_decode($yourJSON, true);

Now you can use foreach to get the data from $myArray array eg:

foreach($myArray['forecast']['forecastday'] as $key => $value)
{
   echo $value['period'];
   echo $value['icon'];
   // etc
}

edited Jun 20, 2020 at 9:12

CommunityBot

11 silver badge

answered Jun 10, 2012 at 9:58

Sarfraz

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2 Comments

Sarfraz Over a year ago

@Eric: To convert it to an array and that's my personal preference :)

Sarfraz Over a year ago

@DavidMorin: See updated answer plz. You did not provide correct json start point in your question first :)

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

You can also convert json to PHP objects:

$myData = json_decode($yourJSON);

foreach($myData->forecast->forecastday as $day) {
   echo $day->period;
   echo $day->icon;
}

EDIT:

I think you can fix the code in your question with this:

<?php
$json_string =    file_get_contents("http://api.wunderground.com/api/7ec5f6510a4656df/geolookup/forecast/q/40121.json");
$parsed_json = json_decode($json_string);
$forecast = $parsed_json->forecast->txt_forecast;
$temp = $forecast->date;
$title = $forecast->forecastday->title;
$for = $forecast->forecastday->fcttext;
echo "Current date is ${temp},  ${title}: ${for}\n";

foreach($forecast->forecastday as $value) {
   echo $value['period'];
   echo $value['icon'];
   // etc
}
?>

edited Jun 20, 2020 at 9:12

CommunityBot

11 silver badge

answered Jun 10, 2012 at 10:05

Eric

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8 Comments

David Morin Over a year ago

Warning: Invalid argument supplied for foreach()

Eric Over a year ago

@DavidMorin: What does print_r($myData->forecast->forecastday) give?

Eric Over a year ago

@DavidMorin: What about print_r($myData->forecast)?

David Morin Over a year ago

with your above edit i get Parse error: syntax error, unexpected T_VARIABLE in

Eric Over a year ago

@DavidMorin: Missing semicolon

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