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Using SQL, I have 5 columns: ssn, lastname, firstname, RF and a flag field. I need to go through this table and where the 4 columns are equal to another row and the value of the flag field in that row is equal to 2050, then delete that 2050 record.

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    Thanks Guys, It appears fairly straightforward once you see it in print.. Really appreciate the help... Commented Jun 24, 2009 at 19:39

4 Answers 4

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delete from MyTable m
where flag = 2050
and exists (
    select 1 from MyTable where
    MyTable.ssn = m.ssn 
        and MyTable.lastname=m.lastname 
        and MyTable.firstname=m.firstname 
        and MyTable.RF=m.RF 
        and MyTable.flag <> 2050
)
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4 
DELETE
     T1
FROM
     My_Table T1
INNER JOIN My_Table T2 ON
     T2.ssn = T1.ssn AND
     T2.last_name = T1.last_name AND
     T2.first_name = T1.first_name AND
     T2.RF_name = T1.RF_name AND
     T2.flag <> T1.flag
WHERE
     T1.flag = 2050
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2 
delete from TableName as tn
where tn.flag = 2050 and
exists (select * from TableName as tn2 where tn.ssn = tn2.ssn
        and tn.lastname = tn2.lastname and tn.firstname = tn2.firstname
        and tn.rf = tn2.rf and tn2.flag <> 2050)
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1 
delete from Table1 
 where flag = 2050 
   and exists (select * 
                 from Table2 
                where ssn = Table1.ssn
                  and lastname = Table1.lastname 
                  and firstname = Table1.firstname 
                  and rf = Table1.rf 
                  and flag <> 2050)
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