Is it possible?
function test()
{
echo "function name is test";
}
5 Answers
The accurate way is to use the __FUNCTION__ predefined magic constant.
Example:
class Test {
function MethodA(){
echo __FUNCTION__;
}
}
Result: MethodA.
1 Comment
mvsagar
FUNCTION works for non-class functions as well. Tried on PHP 7.0.8.
You can use the magic constants __METHOD__ (includes the class name) or __FUNCTION__ (just function name) depending on if it's a method or a function... =)
4 Comments
Alister Bulman
METHOD includes the class name, FUNCTION is just that. The latter is equally available in the method of a class.
PatrikAkerstrand
That's true. But it's often useful to get MyClass::methodName instead of methodName.
Jonny
METHOD does not necessarily return the class name; if the place of calling this is inside a trait, you'll get the trait name. If you want to get the classname of the instance used, use
get_class($this).PatrikAkerstrand
@Jonny: Traits were introduced in PHP 5.4, in 2012. So they weren't a thing when this answer was written in 2009. Please feel free to suggest an edit to update the answer for how PHP works nowadays.
If you are using PHP 5 you can try this:
function a() {
$trace = debug_backtrace();
echo $trace[0]["function"];
}
4 Comments
Luke Cousins
This is incredible resource intensive. Using FUNCTION or METHOD is much more efficient. debug_backtrace() is great if you need more than just the function name though.
Marcio Mazzucato
It's a bad practice to use debug_backtrace() for this purpose
T.Todua
THIS IS THE ONLY CORRECT WAY i have found !!!!!!!!!!!!!!!!!! !!!!!!!!!!!!!!!! !!!!!!!!!!!!!! because
__FUNCTION__ returns parent function name (when the current function is included in parent function)
alds
@tazo todua. can you give an example?
<?php
class Test {
function MethodA(){
return __FUNCTION__ ;
}
}
$test = new Test;
echo $test->MethodA();
?>
Result: "MethodA";
2 Comments
SilverNak
While this code snippet may be the solution, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.
vishva8kumara
You have to return the value instead echo, from the function to echo the result.
<?php
function fun(){
var_dump([
"__FUNCTION__" => __FUNCTION__,
"__METHOD__" => __METHOD__,
]);
}
class C{
function meth(){
var_dump([
"__FUNCTION__" => __FUNCTION__,
"__METHOD__" => __METHOD__,
]);
}
static function static_meth(){
var_dump([
"__FUNCTION__" => __FUNCTION__,
"__METHOD__" => __METHOD__,
]);
}
}
fun();
$o = new C();
$o->meth();
$o->static_meth();
?>
outputs
array(2) {
["__FUNCTION__"]=>
string(3) "fun"
["__METHOD__"]=>
string(3) "fun"
}
array(2) {
["__FUNCTION__"]=>
string(4) "meth"
["__METHOD__"]=>
string(7) "C::meth"
}
array(2) {
["__FUNCTION__"]=>
string(11) "static_meth"
["__METHOD__"]=>
string(14) "C::static_meth"
}
Fwiw if you want to call yourself without knowing/caring about your function name, you'd do
(__METHOD__)();
or perhaps
(__METHOD__)(...func_get_args());
function name1()then use name1 again inside), would save lots of time if you have the same template for lots of functions.