String to char array Java

Question

I am stumped on this and I need some fresh eyes, I'm not sure why this code is doing this.

String string = new String(new char[] {(char) 0x01, (char) 0x02, ... ,(char) 0xFC});

The output is everything it should be up until the last number (the 0xFC) it returns a -4, I know its a hex value, but if I do the same with 252 the decimal value, it gives me a negative as well. I hope this is just a simple solution, and I just can't see it.

Thanks ahead of time.

So you are trying to creating a String from a character array? — Hunter McMillen
– Hunter McMillen, Commented Apr 6, 2012 at 20:32
0xFC is a positive integer; the char type is not signed. The resultant codepoint is U+00FC - Latin Small Letter U With Diaeresis. How are you outputting the String? — McDowell
– McDowell, Commented Apr 6, 2012 at 20:42

Kevin · Accepted Answer · 2012-04-07 04:34:23Z

159

A string to char array is as simple as

String str = "someString"; 
char[] charArray = str.toCharArray();

Can you explain a little more on what you are trying to do?

* Update *

if I am understanding your new comment, you can use a byte array and example is provided.

byte[] bytes = ByteBuffer.allocate(4).putInt(1695609641).array();

for (byte b : bytes) {
   System.out.format("0x%x ", b);
}

With the following output

0x65 0x10 0xf3 0x29

edited Apr 7, 2012 at 4:34

answered Apr 6, 2012 at 20:36

Kevin

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2 Comments

Cody Keasberry Over a year ago

I am trying to send a packet with a byte array or char array to get specific values to the device I have on my closed network. I am making an app remote. just need that array in 9 bytes, to give the specific hex or decimal values.

Daniel Watrous Over a year ago

A nice shortcut of the above is "string".toCharArray(). It can save you a line of code.

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