i need to call a php inside another php file and pass some arguments also. how can i do this?? i tried

include("http://.../myfile.php?file=$name");

• but gives access denied. i read like v must not set allow_url_open to OFF.

if i write like $cmd = "/.../myfile.php?file=".$name"; $out =exec($cmd. " 2>&1"); echo $out;

• gives error as /.../myfiles.php?file=hello: no such file or directory.

how can i solve this???

i need to call a php inside another php file and pass some arguments also. how can i do this?? i tried

include("http://.../myfile.php?file=$name");

• but gives access denied. i read like v must not set allow_url_open to OFF.

if i write like

$cmd = "/.../myfile.php?file=".$name";
$out =exec($cmd. " 2>&1");
echo $out;

• gives error as /.../myfiles.php?file=hello: no such file or directory.

how can i solve this???