i need to call a php inside another php file and pass some arguments also. how can i do this??
i tried

    include("http://.../myfile.php?file=$name");

  - but gives access denied. i read like v must not set allow_url_open to OFF.

if i write like

    $cmd = "/.../myfile.php?file=".$name";
    $out =exec($cmd. " 2>&1");
    echo $out;

 - gives error as /.../myfiles.php?file=hello: no such file or directory.

how can i solve this???