What will be the convolution of u(t) with u(-t) using convolution integral? I am confused about the limits of the integration.
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2\$\begingroup\$ It doesn't exist (diverges). \$\endgroup\$John Doty– John Doty2024-05-04 22:39:28 +00:00Commented May 4, 2024 at 22:39
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\$\begingroup\$ Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. \$\endgroup\$Community– Community Bot2024-05-05 15:41:13 +00:00Commented May 5, 2024 at 15:41
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\$\begingroup\$ convolution of u(t) with itself would exist and would be 0 for t < 0 and t for t >= 0, but convoulution of 2 function u(t) and v(t)=u(-t) would diverge. there is always an infinitely large part where both functions overlap. \$\endgroup\$mond– mond2024-05-07 12:23:47 +00:00Commented May 7, 2024 at 12:23
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