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C++ Program to Copy the Contents of One Array Into Another in the Reverse Order

Last Updated : 23 Jul, 2025
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Given an array, the task is to copy these array elements into another array in reverse array.
Examples: 

Input: array: 1 2 3 4 5 
Output: 5 4 3 2 1 

Input: array: 10 20 30 40 50 
Output: 50 40 30 20 10

Let len be the length of original array. We copy every element original_arr[i] to copy_arr[n-i-1] to get reverse in copy_arr[]. 

C++ 
// C program to copy the contents
// of one array into another
// in the reverse order

#include <stdio.h>

// Function to print the array
void printArray(int arr[], int len)
{
    int i;
    for (i = 0; i < len; i++) {
        printf("%d ", arr[i]);
    }
}

// Driver code
int main()
{
    int original_arr[] = {1, 2, 3, 4, 5};
    int len = sizeof(original_arr)/sizeof(original_arr[0]);

    int copied_arr[len], i, j;
   
    // Copy the elements of the array
    // in the copied_arr in Reverse Order
    for (i = 0; i < len; i++) {
        copied_arr[i] = original_arr[len - i - 1];
    }

    // Print the original_arr
    printf("
Original array: ");
    printArray(original_arr, len);

    // Print the copied array
    printf("
Resultant array: ");
    printArray(copied_arr, len);

    return 0;
}

Output: 
Original array: 1 2 3 4 5 
Resultant array: 5 4 3 2 1

 

Time Complexity: O(len)

Auxiliary Space: O(len)


K
kartik
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