C Program for Program to cyclically rotate an array by one
Last Updated :
23 Jul, 2025
Given an array, cyclically rotate the array clockwise by one.
Examples:
Input : arr[] = {1, 2, 3, 4, 5}
Output : arr[] = {5, 1, 2, 3, 4}
// C++ code for program to
// cyclically rotate an array by one
# include <iostream>
using namespace std;
// Method
void rotate(int arr[], int n)
{
int x = arr[n - 1], i;
for (i = n - 1; i > 0; i--)
arr[i] = arr[i - 1];
arr[0] = x;
}
// Main driver method
int main()
{
int arr[] = {1, 2, 3, 4, 5}, i;
int n = sizeof(arr) /
sizeof(arr[0]);
cout << "Given array is \n";
for (i = 0; i < n; i++)
cout << arr[i];
rotate(arr, n);
cout << "\nRotated array is\n";
for (i = 0; i < n; i++)
cout << arr[i];
return 0;
}
// This code is contributed by jit_t
#include <stdio.h>
void rotate(int arr[], int n)
{
int x = arr[n-1], i;
for (i = n-1; i > 0; i--)
arr[i] = arr[i-1];
arr[0] = x;
}
int main()
{
int arr[] = {1, 2, 3, 4, 5}, i;
int n = sizeof(arr)/sizeof(arr[0]);
printf("Given array is\n");
for (i = 0; i < n; i++)
printf("%d ", arr[i]);
rotate(arr, n);
printf("\nRotated array is\n");
for (i = 0; i < n; i++)
printf("%d ", arr[i]);
return 0;
}
Output
Given array is 12345 Rotated array is 51234
Time Complexity: O(n)
Auxiliary Space: O(1)
Please refer complete article on Program to cyclically rotate an array by one for more details!
