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You're running into a variable scope issue. The variables defined in the while loop that is on the right side of the pipe have their own local scope context, and changes to the variable will not be seen outside of the loop. The while loop is essentially a subshell which gets a COPY of the shell environment, and any changes to the environment are lost at the end of the shell. See this StackOverflow questionStackOverflow question.

UPDATED: I neglected to point out the important fact that the while loop with it's own subshell was due to it being the endpoint of a pipe, I've updated that in the answer.

You're running into a variable scope issue. The variables defined in the while loop that is on the right side of the pipe have their own local scope context, and changes to the variable will not be seen outside of the loop. The while loop is essentially a subshell which gets a COPY of the shell environment, and any changes to the environment are lost at the end of the shell. See this StackOverflow question.

UPDATED: I neglected to point out the important fact that the while loop with it's own subshell was due to it being the endpoint of a pipe, I've updated that in the answer.

You're running into a variable scope issue. The variables defined in the while loop that is on the right side of the pipe have their own local scope context, and changes to the variable will not be seen outside of the loop. The while loop is essentially a subshell which gets a COPY of the shell environment, and any changes to the environment are lost at the end of the shell. See this StackOverflow question.

UPDATED: I neglected to point out the important fact that the while loop with it's own subshell was due to it being the endpoint of a pipe, I've updated that in the answer.

Added the missing information I glossed over in my answer, which geekosaur explained; added 180 characters in body
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jsbillings
jsbillings
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You're running into a variable scope issue. The variables defined in the while loop that is on the right side of the pipe have their own local scope context, and changes to the variable will not be seen outside of the loop. The while loop is essentially a subshell which gets a COPY of the shell environment, and any changes to the environment are lost at the end of the shell. See this StackOverflow question.

UPDATED: I neglected to point out the important fact that the while loop with it's own subshell was due to it being the endpoint of a pipe, I've updated that in the answer.

You're running into a variable scope issue. The variables defined in the while loop have their own local scope context, and changes to the variable will not be seen outside of the loop. The while loop is essentially a subshell which gets a COPY of the shell environment, and any changes to the environment are lost at the end of the shell. See this StackOverflow question.

You're running into a variable scope issue. The variables defined in the while loop that is on the right side of the pipe have their own local scope context, and changes to the variable will not be seen outside of the loop. The while loop is essentially a subshell which gets a COPY of the shell environment, and any changes to the environment are lost at the end of the shell. See this StackOverflow question.

UPDATED: I neglected to point out the important fact that the while loop with it's own subshell was due to it being the endpoint of a pipe, I've updated that in the answer.

Source Link
jsbillings
jsbillings
  • 24.9k
  • 7
  • 58
  • 58

You're running into a variable scope issue. The variables defined in the while loop have their own local scope context, and changes to the variable will not be seen outside of the loop. The while loop is essentially a subshell which gets a COPY of the shell environment, and any changes to the environment are lost at the end of the shell. See this StackOverflow question.