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αғsнιη
αғsнιη
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$ cat data
bob,wag,06/13/1958
ashley,hay,01/23/1983
evan,bert,09/11/1972

To output in a file named output-file and display to STDOUT at the same time:

$ awk -v year=$year="$(\date +%Y)" 'BEGIN{FS="/"} {print $0 "," year-$3}' data | tee output-file
bob,wag,06/13/1958,62
ashley,hay,01/23/1983,37
evan,bert,09/11/1972,48

Or to just output to the same file:

$ awk -v year=$year="$(\date +%Y)" 'BEGIN{FS="/"} {print $0 "," year-$3}' data > output-file

$ cat data
bob,wag,06/13/1958
ashley,hay,01/23/1983
evan,bert,09/11/1972

To output in a file named output-file and display to STDOUT at the same time:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data | tee output-file
bob,wag,06/13/1958,62
ashley,hay,01/23/1983,37
evan,bert,09/11/1972,48

Or to just output to the same file:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data > output-file

$ cat data
bob,wag,06/13/1958
ashley,hay,01/23/1983
evan,bert,09/11/1972

To output in a file named output-file and display to STDOUT at the same time:

$ awk -v year="$(\date +%Y)" 'BEGIN{FS="/"} {print $0 "," year-$3}' data | tee output-file
bob,wag,06/13/1958,62
ashley,hay,01/23/1983,37
evan,bert,09/11/1972,48

Or to just output to the same file:

$ awk -v year="$(\date +%Y)" 'BEGIN{FS="/"} {print $0 "," year-$3}' data > output-file
added output redirection.
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Cbhihe
Cbhihe
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$ cat data
bob,wag,06/13/1958
ashley,hay,01/23/1983
evan,bert,09/11/1972

Just doTo output in a file named output-file and display to STDOUT at the same time:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data | tee output-file
bob,wag,06/13/1958,62
ashley,hay,01/23/1983,37
evan,bert,09/11/1972,48

Or to just output to the same file:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data > output-file

$ cat data
bob,wag,06/13/1958
ashley,hay,01/23/1983
evan,bert,09/11/1972

Just do:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data
bob,wag,06/13/1958,62
ashley,hay,01/23/1983,37
evan,bert,09/11/1972,48

$ cat data
bob,wag,06/13/1958
ashley,hay,01/23/1983
evan,bert,09/11/1972

To output in a file named output-file and display to STDOUT at the same time:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data | tee output-file
bob,wag,06/13/1958,62
ashley,hay,01/23/1983,37
evan,bert,09/11/1972,48

Or to just output to the same file:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data > output-file
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Cbhihe
Cbhihe
  • 2.9k
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  • 33

$ cat data
bob,wag,06/13/1958
ashley,hay,01/23/1983
evan,bert,09/11/1972

Just do:

$ awk -v year=$(\date +%Y) 'BEGIN{FS="/"} {print $0 "," year-$3}' data
bob,wag,06/13/1958,62
ashley,hay,01/23/1983,37
evan,bert,09/11/1972,48