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You should not be doing mv or cp inside awk. The following works:

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="$(echo $i | awk -F'_' '{print $1}')"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

However, instead of awk, you could use the % operator in bash to remove everything after the first underscore to get the directory name.

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="${i%%_*}"
  mkdir -p -- "$dir_name"
  cp -- "$i" "$dir_name"
done

(use mv instead of cp if you want to move)

You should not be doing mv or cp inside awk. The following works:

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="$(echo $i | awk -F'_' '{print $1}')"
  mkdir -p -- "$dir_name"
  cp -- "$i" "$dir_name"
done

However, instead of awk, you could use the % operator in bash to remove everything after the first underscore to get the directory name.

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="${i%%_*}"
  mkdir -p -- "$dir_name"
  cp -- "$i" "$dir_name"
done

(use mv instead of cp if you want to move)

You should not be doing mv or cp inside awk. The following works:

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="$(echo $i | awk -F'_' '{print $1}')"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

However, instead of awk, you could use the % operator in bash to remove everything after the first underscore to get the directory name.

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="${i%%_*}"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

(use mv instead of cp if you want to move)

You should not be doing mv or cp inside awk. The following works:

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="$(echo $i | awk -F'_' '{print $1}')"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

However, instead of awk, you could use the % operator in bash to remove everything after the first underscore to get the directory name.

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="${i%%_*}"
  mkdir -p -- "$dir_name"
  cp -- "$i" "$dir_name"
done

(use mv instead of cp if you want to move)

You should not be doing mv or cp inside awk. The following works:

for i in $(find . -type f) ; do
  dir_name="$(echo $i | awk -F'_' '{print $1}')"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

However, instead of awk, you could use the % operator in bash to remove everything after the first underscore to get the directory name.

for i in $(find . -type f) ; do
  dir_name="${i%%_*}"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

(use mv instead of cp if you want to move)

You should not be doing mv or cp inside awk. The following works:

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="$(echo $i | awk -F'_' '{print $1}')"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

However, instead of awk, you could use the % operator in bash to remove everything after the first underscore to get the directory name.

for i in * ; do
  [ -f "$i" ] || continue
  dir_name="${i%%_*}"
  mkdir -p "$dir_name"
  cp "$i" "$dir_name"
done

(use mv instead of cp if you want to move)