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@NelloDraws It will not work if the value in $variable contains characters that need to be encoded in JSON strings, such as double quotes, tabs, and newlines.

Kusalananda
– Kusalananda ♦

2023-06-01 19:41:49 +00:00
Commented Jun 1, 2023 at 19:41

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Correct minor typos or mistakes
Clarify meaning without changing it
Add related resources or links
Always respect the author’s intent
Don’t use edits to reply to the author

create code fences with backticks ` or tildes ~
```
like so
```
add language identifier to highlight code
```python
def function(foo):
print(foo)
```
put returns between paragraphs
for linebreak add 2 spaces at end
_italic_ or **bold**
indent code by 4 spaces
backtick escapes `like _so_`
quote by placing > at start of line
to make links (use https whenever possible)

<https://example.com>

[example](https://example.com)

<a href="https://example.com">example</a>

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